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anonymous
 5 years ago
how do i get the center, vertices, foci, and eccentricity of 9x^2+4y^236x+8y_31=0?
anonymous
 5 years ago
how do i get the center, vertices, foci, and eccentricity of 9x^2+4y^236x+8y_31=0?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it looks like the equation for a circle or ellipse

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(9x^2 36x +n) + (4y^2 +8y +m) = 31 +n+m complete the squares to find n and m

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0n = (36/2)^2 m=(8/2)^2 (9x^2 36x +18^2) + (4y^2 +8y + 4^2) = 31+18^2+4^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.09(x^2 4x + 9^3) + 4(y^2 +2y + 4) = 371.... if i did it right in me head

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(3x  18)^2 + (2y +4)^2 = 371 3(x6)^2 + 2(y+2)^2 = 371 is what I ge so far

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0divide evertyhing by 371 and see what you can work out I guess...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and dont do stupid mistakes like I did..... that 3 and 2 dont get pulled out....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.09(x^2 4x + 9^3) + 4(y^2 +2y + 4) = 371 is the correct way... solve your quadratics to get 2 solutions.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im gonna get it one way or another..... ignore that 9^3 flub... 9(x^2 4x + 36) + 4(y^2 +2y + 4) = 371
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