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anonymous

  • 5 years ago

Equation: 10(x-1)(x-2)(x-3)=1 has three real solutions a<b<c find A,B,C Hint: ask what the solutions are if the right hand side is 0 instead of 1, and use Newton's Method

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  1. radar
    • 5 years ago
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    Using the Hint, I say self what would be solution if the 1 on the right was a 0?. Well 10 is 10 so one or two or may be all three of the remaining factors are o, then x=1, x=2, x=3 But it isn't a zero, it is 1 on the right. So now what do I do?

  2. anonymous
    • 5 years ago
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    i truly have no clue how tho do this problem

  3. radar
    • 5 years ago
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    As you may have guessed, I don't either....If it was a zero on the right! I think I could.lol

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