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anonymous
 5 years ago
dos the system have on solution, no solution, or an infinite number of solutions?
x+y=6
x+y=4
a. one. b. none. c. infinite number
anonymous
 5 years ago
dos the system have on solution, no solution, or an infinite number of solutions? x+y=6 x+y=4 a. one. b. none. c. infinite number

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0none, x+y can only have one solution..otherwise: 4+5 = 9 4+5 = 3 just nonsense i tell ya....nonsense!! :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0graphically, and if it aint a word it should be, these are parallel lines that never intersect

radar
 5 years ago
Best ResponseYou've already chosen the best response.0How about this one? x + y =4 x + y =0 Would x=2\[y=\sqrt{4}\] be an answer????

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0same slopes, different "y intercepts"....nope

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y=x y = x+4 x = x+4 x+x = 4 0 = 4 nonsense :)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Just wondering, as the square root of 4 is +2 or 2 and they when substituted for y and if x=2 would produce those two answers. Kind caught me off guard.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02+2 = 4 2+2 = 0 still not a good solution :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Square root of 4 is +2 (by definition), kids [NOT 2]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0even if 2 was available to us it doesnt change the results of 0=4; which is absurd....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0He was implying it could equal 2 or 2 (one in each)  yes, of course that is absurd, but I thought I would tell him the flaw in his thinking.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, 2 = 2 is equally nonsensical :) If we cant pin down x at a single value, then its futile.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks, you can see where the flaw would 2 +(+2)=4 and 2 + (2) = 0 However, it has been revealed that the negative root of a variable is not usable or shouldn't be used in this case. Now please note. There was no way to solve the two equations to come up with that ridiculous answer!
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