## anonymous 5 years ago dos the system have on solution, no solution, or an infinite number of solutions? x+y=6 x+y=4 a. one. b. none. c. infinite number

1. amistre64

none, x+y can only have one solution..otherwise: 4+5 = 9 4+5 = 3 just nonsense i tell ya....nonsense!! :)

2. anonymous

lol thank yiu

3. amistre64

graphically, and if it aint a word it should be, these are parallel lines that never intersect

How about this one? x + y =4 x + y =0 Would x=2$y=\sqrt{4}$ be an answer????

5. amistre64

same slopes, different "y intercepts"....nope

6. amistre64

y=-x y = -x+4 -x = -x+4 -x+x = 4 0 = 4 nonsense :)

Just wondering, as the square root of 4 is +2 or -2 and they when substituted for y and if x=2 would produce those two answers. Kind caught me off guard.

8. amistre64

2+2 = 4 2+2 = 0 still not a good solution :)

9. anonymous

Square root of 4 is +2 (by definition), kids [NOT -2]

10. amistre64

even if -2 was available to us it doesnt change the results of 0=4; which is absurd....

11. anonymous

He was implying it could equal 2 or -2 (one in each) - yes, of course that is absurd, but I thought I would tell him the flaw in his thinking.

12. amistre64

yeah, 2 = -2 is equally nonsensical :) If we cant pin down x at a single value, then its futile.