A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
I am working on the taylor series portion of the course and had a question:
anonymous
 5 years ago
I am working on the taylor series portion of the course and had a question:

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is the taylor series representation of ln (x+1) = \[\sum_{0}^{\infty}((1)^{n+1}X ^{n})/n\] I worked this out on my own and wanted to know if this is correct. Thanks!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correction I guess you have to start the series at 1 because of 0 being undefined.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0two ways i can think to approach this. one is to calculate the nth derivative of ln[1+x], and find \[(1)^{n+1}/(1+x)^n\] this value at x=0 is simply (1)^n or (1)^(n+1) then proceed with taylor's formula. else use the geometric series representation of closed form (assumes abs[x]<1)\[\frac{1}{1+x}=\sum_{n=0}^{\infty}(x)^n\] then integrate both sides with respect to x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Solved: Thanks gamesguru. I also just found out that Wikipedia has the Taylor series listed and my answer was right.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.