Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

In a sample of 26 hand-held calculators, 20 are known to be nonfunctional. If 6 of these calculators are selected at random, what is the probability that exactly 4 in the selection are nonfunctional? Round to the nearest thousandth.
A. 0.667
B. 0.316
C. 0.769
D. 0.300
E. 0

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- jamiebookeater

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Draw a probability tree. I would, but I don;t have the patience, and hate statistics with a passion.

- amistre64

I know you have a 76.9% chance of picking one the first time..... but what to do after than I would have to read up on :)

- amistre64

I would assume our initial options would lead to these
b,b,b,b,b,b
b,b,b,b,b,g
b,b,b,b,g,g
b,b,b,g,g,g
b,b,g,g,g,g
b,g,g,g,g,g
g,g,g,g,g,g

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

\[\frac{20 \times 19 \times 18 \times 17 \times 6 \times 5}{26 \times 25 \times 24 \times 23 \times 22 \times 21} \times ^6 C_4\]

- anonymous

Well I tried that but that doesn't get me close to any of the solutions?

- anonymous

Of course it does, I just told you it.

- anonymous

Do you know what 6C4 means?

- anonymous

\[^NC_R \equiv \frac{n!}{n!(n-r)!}\]

- anonymous

Yes lol sorry I think I just plugged in my calc wrong was all! Thanks a bunch!

- anonymous

You have to explain to me why that is the answer now, though.

- amistre64

20/26; then the odds go to 19/25, then to 18/24 .....

- anonymous

My definition of NCR has n! on the bottom when it should be r!, apologies to anyone confused.

- anonymous

well the equation you just gave me is saying the number of combinations of n elements taken r times

- amistre64

thats last bit is combinatorical .... i think

- anonymous

Ya I'm pretty sure it is combinatorical just not positive on how to solve it via the way my book is showing me lol

- anonymous

Sort of - You need to pick 4 non functioning, and 2 functioning.
The first one gives you the overall odds of each in turn, and the second gives you the different orders you can do it in.

- anonymous

uh ok I'm confused again.... Can you show me on http://www.dabbleboard.com/draw?b=Guest644716&i=0&c=3327a9e1158d904a38fbad735c24ed28cad7bcd9

- anonymous

No, sorry, I have stuff to do. Draw a probability tree.

- anonymous

ok Thanks for helping though! Much appreciated... I'll mess around with it until I figure it out:)

- anonymous

amistre64....what were you trying to say when you posted...20/26; then the odds go to 19/25, then to 18/24? if I keep working my way down what does that do?

- anonymous

- anonymous

Let's say you choose FFFFNN, the odds are:
(20/26 x 19/25 x 18/24 x 17/23) x (6/22 x 5/21)
However, you could actually do this in any order, so you have to multiply it by 6C2

Looking for something else?

Not the answer you are looking for? Search for more explanations.