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anonymous

  • 5 years ago

Approximate the sum of the series correct to four decimal places. sum n=1,infinity ((-1)^(n-1) n^2)/(10^n) I know how to finish the equation once I have the number I need to go up to, but I don't know how to find that number, can anyone help?

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  1. anonymous
    • 5 years ago
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    You can do the same thing with this one, just solve another equality without the (-1)^(n-1) n^2/(10^n)<0.0001 This should give you the number of terms

  2. anonymous
    • 5 years ago
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    It doesn't give me an error though

  3. anonymous
    • 5 years ago
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    The error of the approximation?

  4. anonymous
    • 5 years ago
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    It wants me to find the sum.

  5. anonymous
    • 5 years ago
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    I think the easiest way to do this one is write out the terms, maybe the first 3 or 4. and then find the first term that is less than 0.0001. Add all of the terms before this term and you get the approximate sum correct to 0.0001

  6. anonymous
    • 5 years ago
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    (cause i just realized in the equality was like 10^n which you can't really solve for easily )

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