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anonymous
 5 years ago
Approximate the sum of the series correct to four decimal places.
sum n=1,infinity ((1)^(n1) n^2)/(10^n)
I know how to finish the equation once I have the number I need to go up to, but I don't know how to find that number, can anyone help?
anonymous
 5 years ago
Approximate the sum of the series correct to four decimal places. sum n=1,infinity ((1)^(n1) n^2)/(10^n) I know how to finish the equation once I have the number I need to go up to, but I don't know how to find that number, can anyone help?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can do the same thing with this one, just solve another equality without the (1)^(n1) n^2/(10^n)<0.0001 This should give you the number of terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It doesn't give me an error though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The error of the approximation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It wants me to find the sum.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think the easiest way to do this one is write out the terms, maybe the first 3 or 4. and then find the first term that is less than 0.0001. Add all of the terms before this term and you get the approximate sum correct to 0.0001

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(cause i just realized in the equality was like 10^n which you can't really solve for easily )
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