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anonymous

  • 5 years ago

A person standing close to the edge on the top of an 80-foot building throws a ball vertically upward with an initial velocity of 64 feet per second. The function s(t) = -16t 2 + 64t + 80 describes the ball's height above the ground, s(t), in feet, t seconds after it is thrown. (a) After how many seconds does the ball reach its maximum height? (b) Find the maximum height of the ball.

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  1. anonymous
    • 5 years ago
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    Take the derivative, this will give you a velocity function. v(t)= -32t+64 Solve for when the velocity is 0 0=-32t+64

  2. anonymous
    • 5 years ago
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    how didu get these numbers

  3. anonymous
    • 5 years ago
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    Derivative of each term of your position function for example on derivatives: derivative of x^2 = 2x derivative of 3x^2= 6x derivative of 4x=4 etc...

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