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smurfy14

  • 5 years ago

ln2000=ln20+0.825t what is the answer and how do you get it?

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  1. myininaya
    • 5 years ago
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    put the natural logs on one side and then combine them using lnx/y=lnx-lny property and then base e both sides

  2. anonymous
    • 5 years ago
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    ln 2000 - ln 20 = 0.825t ln (2000/20) = 0.825 t t = (ln(2000/20)) / 0.825

  3. myininaya
    • 5 years ago
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    i mean no base e

  4. myininaya
    • 5 years ago
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    lol

  5. smurfy14
    • 5 years ago
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    so it goes like this: ln200/ln20=.825t ln100=.825t t=5.582?

  6. myininaya
    • 5 years ago
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    no it goes like this first step subtract ln20 on both sides giving you: ln2000-ln20=.0825t

  7. myininaya
    • 5 years ago
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    now we can write ln[(2000/20)]=.0825t

  8. myininaya
    • 5 years ago
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    ln(100)=.0825t

  9. myininaya
    • 5 years ago
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    to solve for t we just divide now by .0825giving us [ln(100)]/(.0825)=t

  10. myininaya
    • 5 years ago
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    remember that property: ln(x/y)=lnx-lny?

  11. smurfy14
    • 5 years ago
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    but isnt that what i did? im confused...you said to ln2000-ln20 (subtract) but instead you divided?

  12. smurfy14
    • 5 years ago
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    so what would be the final answer?

  13. myininaya
    • 5 years ago
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    thats how i would write my final answer. ln(x/y) does not equal lnx/lny

  14. smurfy14
    • 5 years ago
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    oh ok i see so final answer when put in calc would be??

  15. myininaya
    • 5 years ago
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    > ln(100.0)/(.0825); 55.82024467 >

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