smurfy14
  • smurfy14
ln2000=ln20+0.825t what is the answer and how do you get it?
Mathematics
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SOLVED
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chestercat
  • chestercat
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myininaya
  • myininaya
put the natural logs on one side and then combine them using lnx/y=lnx-lny property and then base e both sides
anonymous
  • anonymous
ln 2000 - ln 20 = 0.825t ln (2000/20) = 0.825 t t = (ln(2000/20)) / 0.825
myininaya
  • myininaya
i mean no base e

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myininaya
  • myininaya
lol
smurfy14
  • smurfy14
so it goes like this: ln200/ln20=.825t ln100=.825t t=5.582?
myininaya
  • myininaya
no it goes like this first step subtract ln20 on both sides giving you: ln2000-ln20=.0825t
myininaya
  • myininaya
now we can write ln[(2000/20)]=.0825t
myininaya
  • myininaya
ln(100)=.0825t
myininaya
  • myininaya
to solve for t we just divide now by .0825giving us [ln(100)]/(.0825)=t
myininaya
  • myininaya
remember that property: ln(x/y)=lnx-lny?
smurfy14
  • smurfy14
but isnt that what i did? im confused...you said to ln2000-ln20 (subtract) but instead you divided?
smurfy14
  • smurfy14
so what would be the final answer?
myininaya
  • myininaya
thats how i would write my final answer. ln(x/y) does not equal lnx/lny
smurfy14
  • smurfy14
oh ok i see so final answer when put in calc would be??
myininaya
  • myininaya
> ln(100.0)/(.0825); 55.82024467 >

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