ln2000=ln20+0.825t what is the answer and how do you get it?

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ln2000=ln20+0.825t what is the answer and how do you get it?

Mathematics
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put the natural logs on one side and then combine them using lnx/y=lnx-lny property and then base e both sides
ln 2000 - ln 20 = 0.825t ln (2000/20) = 0.825 t t = (ln(2000/20)) / 0.825
i mean no base e

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Other answers:

lol
so it goes like this: ln200/ln20=.825t ln100=.825t t=5.582?
no it goes like this first step subtract ln20 on both sides giving you: ln2000-ln20=.0825t
now we can write ln[(2000/20)]=.0825t
ln(100)=.0825t
to solve for t we just divide now by .0825giving us [ln(100)]/(.0825)=t
remember that property: ln(x/y)=lnx-lny?
but isnt that what i did? im confused...you said to ln2000-ln20 (subtract) but instead you divided?
so what would be the final answer?
thats how i would write my final answer. ln(x/y) does not equal lnx/lny
oh ok i see so final answer when put in calc would be??
> ln(100.0)/(.0825); 55.82024467 >

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