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smurfy14
 5 years ago
ln2000=ln20+0.825t what is the answer and how do you get it?
smurfy14
 5 years ago
ln2000=ln20+0.825t what is the answer and how do you get it?

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0put the natural logs on one side and then combine them using lnx/y=lnxlny property and then base e both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ln 2000  ln 20 = 0.825t ln (2000/20) = 0.825 t t = (ln(2000/20)) / 0.825

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0so it goes like this: ln200/ln20=.825t ln100=.825t t=5.582?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0no it goes like this first step subtract ln20 on both sides giving you: ln2000ln20=.0825t

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0now we can write ln[(2000/20)]=.0825t

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0to solve for t we just divide now by .0825giving us [ln(100)]/(.0825)=t

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0remember that property: ln(x/y)=lnxlny?

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0but isnt that what i did? im confused...you said to ln2000ln20 (subtract) but instead you divided?

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0so what would be the final answer?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0thats how i would write my final answer. ln(x/y) does not equal lnx/lny

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok i see so final answer when put in calc would be??

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0> ln(100.0)/(.0825); 55.82024467 >
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