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anonymous

  • 5 years ago

Sarah draws a card from a deck of 52 cards. She receives 40 cents for a heart, 50 cents for an ace, and 90 cents for the ace of hearts. The cost of a draw is 15 cents. How much will Sarah lose if she plays this game?

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  1. amistre64
    • 5 years ago
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    if I played Id lose 15 cents

  2. anonymous
    • 5 years ago
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    thats what I thought but when i put that as my anwser it said it was wrong

  3. amistre64
    • 5 years ago
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    how many draws she get?

  4. anonymous
    • 5 years ago
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    it doesnt say thats all the info i got

  5. anonymous
    • 5 years ago
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    did you try 0?

  6. amistre64
    • 5 years ago
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    well then, the most she could lose is 15 cents..... but maybe those aint vegas odds :)

  7. anonymous
    • 5 years ago
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    no I havent I have one more try to get it right you get four and i used them all up

  8. amistre64
    • 5 years ago
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    your allowed to miss a few questions right? :)

  9. anonymous
    • 5 years ago
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    haha yea i missed one already lol i guess i could miss this one i have two more questions that im about to post if you could help me with them that would be great

  10. amistre64
    • 5 years ago
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    i aint none to good with probability yet..... but i could take a gander at 'em

  11. anonymous
    • 5 years ago
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    there is something wrong with this question this is the solution i got...E = 40(12/52)+50(3/52)+90(1/52) = 13.8. This means Sarah expects to win 13.8 cents. However, she pays 15 cents to play the game. Therefore, she actually loses money: 13.8-15 = 1.2 cents.

  12. amistre64
    • 5 years ago
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    why would sarah expect to win a game? i agree, that question is bad...maybe even evil..... lol

  13. anonymous
    • 5 years ago
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    can it be 40(1/4)+50(1/13)+90(1/52) ?

  14. anonymous
    • 5 years ago
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    okay I understand it now just talked to someone in class about it...because there's the option for the ace of hearts you have to take that out of the other options,....you cant win both cash prices at once

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