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anonymous

  • 5 years ago

what is the area and width of a triangle with the measures of 29.6=21+2w

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  1. amistre64
    • 5 years ago
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    i take it that that is the perimeter of the triangle in question...

  2. anonymous
    • 5 years ago
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    yes

  3. amistre64
    • 5 years ago
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    make s = the area is half the perimeter then use Herons formula sqrt(s(s-a)(s-b)(s-c)) = area. if I remember it correctly

  4. amistre64
    • 5 years ago
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    that 2w seems a bit off, I would assume that means that 2 of the legs are of equal length and that they measure "w" in length

  5. amistre64
    • 5 years ago
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    maybe it means after you find the area, use what you know for "w" to plug into the normal area formula. Area = width(height)/2

  6. anonymous
    • 5 years ago
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    can you answer this one..... what is the area and width of a rectangle with the perimeter of 29.6 and the length of 10.5..? i used P=2l+2w but i dont know how to solve it

  7. amistre64
    • 5 years ago
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    29.6 - 21 = 8.6 which dont make no sense, side thats 21, you would need 2 more sides that add up to at least 21. All thats left here is 17.2. Im thinking that either theres imformation missing or that this dont make a triangle

  8. amistre64
    • 5 years ago
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    but then again, im using my georgia math....

  9. anonymous
    • 5 years ago
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    well can you answer this... Use P=(2)l+(2)w so far I have 20.6=(2)l+(2)3.1 can you solve that so i know the width?

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