## anonymous 5 years ago what is the area and width of a rectangle with the perimeter of 29.6 and the length of 10.5..? i used P=2l+2w but i dont know how to solve it

You are on the right track. You now just have to find w from your perimeter formula and other information, then use that result, with your knowledge of l, to find the area of the rectangle. So$P=2l+2w \rightarrow 2w=P-2l \rightarrow w=\frac{P-2l}{2}=\frac{29.6-2(10.5)}{2}$$=4.3$So now that you have w=4.3, you can use w and l to find the area:$A=lw=10.5 \times 4.3 =45.15$square units.