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linda

  • 5 years ago

solve for x to the nearest thousandth: 100 ln (2x-3)-10=102

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  1. anonymous
    • 5 years ago
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    so is the equation 100(2x-3)-10=102?

  2. Linda
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    So no ln?

  4. Linda
    • 5 years ago
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    wait theres an ln in it before the 2x-3

  5. Linda
    • 5 years ago
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    sorry, the ln is there

  6. anonymous
    • 5 years ago
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    Use math properties to isolate x. Start by adding 10 to both sides, then divide by 100 on both sides etc.

  7. Linda
    • 5 years ago
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    okay, then what should i do with the ln?

  8. Linda
    • 5 years ago
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    the ln part confuses me, im not too good with it

  9. anonymous
    • 5 years ago
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    ok, so first im pretty sure that you have to distribute the 100 to the 2 and -3 then you should put the -300 and the -10 together

  10. anonymous
    • 5 years ago
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    making -310, with this you should add it to the other side of the = sign

  11. anonymous
    • 5 years ago
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    e is the inverse of ln. So if both sides are e raised to a power. You will get e^(ln(2x-3)=e^1.12

  12. Linda
    • 5 years ago
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    but how do i solve for the x?

  13. anonymous
    • 5 years ago
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    100(2x-3)-10=102 200x-300-10=102 200x-310=102 200x=412 because you added the 210 the the 102 then you should divide 400 by 200 that should leave you with x=2.06

  14. Linda
    • 5 years ago
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    you left out the ln (natural logarithm)

  15. anonymous
    • 5 years ago
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    So e^(ln) is 1. So the left side goes to 2x-3. So you should get 2x-3=e^(1.12)

  16. Linda
    • 5 years ago
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    ok, so i set 2x-3=1.12. then i added 3 to 1.12 and got 2x=4.12.

  17. Linda
    • 5 years ago
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    is that right?

  18. anonymous
    • 5 years ago
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    No. You left out the e. E is a function in itself just like ln. So you can use a calculator to find the value of e^1.12. Then you can continue with your process.

  19. Linda
    • 5 years ago
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    ok, so i got 3.065 for e^1.12. then i added 3 to that. i got 2x=6.065. then i divided by two and got x=3.033. sound right?

  20. anonymous
    • 5 years ago
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    Yes!

  21. anonymous
    • 5 years ago
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    You can always check by plugging your value of x back into the equation and seeing if it's equal.

  22. Linda
    • 5 years ago
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    yay!! thank you so much!! :)

  23. anonymous
    • 5 years ago
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    No problem. :)

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