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no, that's not right.
\[(1 / 2)9\times9\times4\]
is the triangle an equilateral triangle, a right angle triangle or an isosceles triangle?
would the area be \[(1 / 2)81\left( 4 \right)=162 \]
how did you arrive at (1/2)*9*9? How do you know the height of the triangle is 9?
the bottom part has a 9 and has a tick mark so all three sides are equal and 4 in the height
still, the height is not 9, only the sides are 9.
you have to calculate the height of the triangle and plug it in the formula 1/2 base*height. base is 9.
9 is the base
right. calculate height using Pythagoras theorem
V=Bh= (1/2*9*9)(4)= (40.5)(4)=162
I am talking about the height of the triangle. for an equilateral triangle of side 9, how do you calculate its area?
draw an equilateral triangle on a piece of paper. how do you calculate its height?
ok good, what is a, b and c in an equilateral triangle?
a=9 b=9 c=162
no, that is not right. http://math.about.com/od/formulas/ss/areaperimeter.htm In that picture, the area of the triangle is 1/2b*h. so, what do you know about an equilateral triangle that will make finding the height easier?
the height in my picture is 4
no, that is not the height of the triangle, it is the height of the prism. I am talking about the height of the triangle. The volume of the prism is the area of the triangle times the height of the prism, correct? so you know the height of the prism. Now you need to find the area of the triangle. So, in order to do that you need to find the height of the triangle, so that you can put it in the formula 1/2b*h.