anonymous
  • anonymous
Square root of X (X+1) Derivatives help
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Is it \[\sqrt{x}(x+1)\] or \[\sqrt{x(x+1)}\] ?
anonymous
  • anonymous
√x (x+1)
anonymous
  • anonymous
Ok, so \[x^{1/2}(x+1)\]

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anonymous
  • anonymous
I'd probably multiply it out, then take the derivative.
anonymous
  • anonymous
If it is all under the radical then you'll need to use the chain rule instead.
anonymous
  • anonymous
Yes you are right on both cases.
anonymous
  • anonymous
My bad lol. I thought you were the one needing help polpak haha. Sorry.
anonymous
  • anonymous
\[\frac{d}{dx}[ x^{3/2} + x^{1/2}] = \frac{3x^{1/2}}{2} + \frac{1}{2x^{1/2}}\] Then simplify.
anonymous
  • anonymous
how did u get x^3/2+X^1/2
anonymous
  • anonymous
\[x^{1/2}(x+1) = x^{1/2}*x^1 + x^{1/2}*1 = x^{\frac{1}{2}+1} +x^{1/2}\] \[ = x^{3/2} +x^{1/2}\]

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