solve 3x^2+13x+4=0

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solve 3x^2+13x+4=0

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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It doesn't look like you can factor, so you'll have to set the equation equal to zero (subtract 8 from both sides) and use the Quadratic Formula. (It's hard to type out, so here's a picture. http://www.scientificpages.net/math/images/Quadratic_Formula.gif) A is the x squared coefficient, b is the x coefficient, and c is the constant. So you just plug in the numbers 3, 13, and 4 into the formula for a, b, and c. Remember also that with the plus and minus you'll get two answers.
=(1x+4)(3x+1) x=-4/1, -1/3
the factor is 12 * 1 3x^2 + 13x + 4, a =3,b=13,c=4 ac=12 , factor is 1*12 3x^2+12x+1x+4=0 3x(x+4)+1(x+4)=o (3x+1)(x+4)=0 x=-1/3 , x =-4

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