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linda
 5 years ago
14e^9x42 +5=500
linda
 5 years ago
14e^9x42 +5=500

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is the 9x the exponent on e or is it the quantity of (9x42)?

Linda
 5 years ago
Best ResponseYou've already chosen the best response.09x42 is the whole exponent on the e

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok. Kind of like the last problem. Subtract the 5 so you get 14e^(9x42)=495.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Divide both sides by 14 to get e^(9x42)=495/14

Linda
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i did that, and then i divided 14 by 495 so i ended up with e^9x42=35.357

Linda
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok great so that was right, im stuck after that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok. Now we go back to the ln and e functions. Like I said before they are inverses of each other so they cancel each other out. e^(ln1)=1 and ln(e)=1. We need to use these properties again here.

Linda
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so do i change e to ln?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What you need to do is get rid of the e so you can isolate x. To do this take ln of both sides.

Linda
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh, so does that leave me with just 9x42 on one side?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes and then ln of whatever that number is on the other.

Linda
 5 years ago
Best ResponseYou've already chosen the best response.0ok, makes sense now. thanks!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're welcome. I don't know if you need exact form or approximate, but seems like you are getting it.

Linda
 5 years ago
Best ResponseYou've already chosen the best response.0ok, makes sense now. thanks!
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