A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

Two small nonconducting spheres have a total charge of 90.0 micro Coulombs. (a) When placed 1.16 m apart, the force each exerts on the other is 12.0 N and is repulsive. What is the charge on each? (b) What if the force were attractive? r = 1.16m F = 12.0 N k = (F x r^2)/(Q1 x k) = Q2, (F x r^2)/(Q2 x k) = Q1 I know that I'm supposed to find Q1 and Q2, but I can only find one in terms of the other. I have Q2 = (1.796 x 10^(-9) C^2)/Q1, but that's as far as I can get. Any pointers?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k = [8.99 \times 10^{9} N \times m ^{2}/C ^{2}\]

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[Q_1 + Q_2 = Q_{tot}\] \[F_{el} = {{k Q_1Q_2} \over {d^2}}\] \[Q_1 = {d^2 F_{el} \over k Q_2}\] \[{d^2 F_{el} \over {k Q_2}} + Q_2 = Q_{tot}\] Multiplying by Q2, \[Q_2 ^2 + ({d^2 F_{el} \over k})Q_2 - Q_{tot} = 0\] \[\Delta = ({d^2.F_{el} \over k})^2 + 4Q_{tot}\] \[Q_2 = {{({d^2F_{el} \over k}) \pm \sqrt{\Delta}} \over 2}\] There's gonna be a lot of work when really substituting the values...

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.