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anonymous

  • 5 years ago

1/(a-b) + 4/(b-a) - 8/(a+b) - (11a - 5b)/(b^2-a^2) simplify and plz explain your answer...

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  1. anonymous
    • 5 years ago
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    note (a-b) = -(b-a) , and (b^2 - a^2) = (b+a)(b-a) Multiply through by whatever you need to to get it all over this fraction and see what cancels. I can;t be bothered with the leg work

  2. anonymous
    • 5 years ago
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    Oh, it cancel down very nicely. You could say it cancels down to virtually 'nothing'...

  3. anonymous
    • 5 years ago
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    so you mean it's zero?

  4. anonymous
    • 5 years ago
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    I'm afraid you'll have to work it out first

  5. anonymous
    • 5 years ago
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    I'll give you a clue, 1/(a-b) = -1/(b-a) so the first two become 3/(b-a) If you want it all over b^2-a^2 you need to multiply this by (b+a) and the other fraction over (a+b) by (b-a)

  6. anonymous
    • 5 years ago
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    I thought you said you were gonna test my skills. I am disappoint. Goodnight.

  7. anonymous
    • 5 years ago
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    well geez I was looking for help not criticism...

  8. anonymous
    • 5 years ago
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    goodnight yourself

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spraguer (Moderator)
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