anonymous
  • anonymous
1/(a-b) + 4/(b-a) - 8/(a+b) - (11a - 5b)/(b^2-a^2) simplify and plz explain your answer...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
note (a-b) = -(b-a) , and (b^2 - a^2) = (b+a)(b-a) Multiply through by whatever you need to to get it all over this fraction and see what cancels. I can;t be bothered with the leg work
anonymous
  • anonymous
Oh, it cancel down very nicely. You could say it cancels down to virtually 'nothing'...
anonymous
  • anonymous
so you mean it's zero?

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anonymous
  • anonymous
I'm afraid you'll have to work it out first
anonymous
  • anonymous
I'll give you a clue, 1/(a-b) = -1/(b-a) so the first two become 3/(b-a) If you want it all over b^2-a^2 you need to multiply this by (b+a) and the other fraction over (a+b) by (b-a)
anonymous
  • anonymous
I thought you said you were gonna test my skills. I am disappoint. Goodnight.
anonymous
  • anonymous
well geez I was looking for help not criticism...
anonymous
  • anonymous
goodnight yourself

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