anonymous
  • anonymous
how do you solve these problems: 2n(squared) - 11n + 15 and -3n(squared) - 75
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
are you dealing with imaginary numbers?
anonymous
  • anonymous
no i am dealing with factoring polynomials
anonymous
  • anonymous
so 2n^2-11n+15 = 2n^2 -6n-5n+15

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anonymous
  • anonymous
thank you so much!!
anonymous
  • anonymous
-3n^2-75=0--------> n^2=-25
anonymous
  • anonymous
thank you soo much!!
anonymous
  • anonymous
you are welcome. note that for the second equation, you will have imaginary roots.
radar
  • radar
Since we are tasked to factor the polynomials, take a close look at the second equation.\[-3n ^{2}-75\]
radar
  • radar
It is a factor problem, extract the -3 which is present in both terms.\[-3(n ^{2}+25)\]
radar
  • radar
Thats is about as far as you can go with this.
anonymous
  • anonymous
That's true, unless the right hand side is specified in the equation.
radar
  • radar
I didn't notice any but if it is zero, we would have the situation that you mentioned and probably doehrman hasn't got into complex number yet.
anonymous
  • anonymous
yes, you are right

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