A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
how do you solve these problems: 2n(squared)  11n + 15 and
3n(squared)  75
anonymous
 5 years ago
how do you solve these problems: 2n(squared)  11n + 15 and 3n(squared)  75

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you dealing with imaginary numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i am dealing with factoring polynomials

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 2n^211n+15 = 2n^2 6n5n+15

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03n^275=0> n^2=25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are welcome. note that for the second equation, you will have imaginary roots.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Since we are tasked to factor the polynomials, take a close look at the second equation.\[3n ^{2}75\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0It is a factor problem, extract the 3 which is present in both terms.\[3(n ^{2}+25)\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Thats is about as far as you can go with this.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's true, unless the right hand side is specified in the equation.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't notice any but if it is zero, we would have the situation that you mentioned and probably doehrman hasn't got into complex number yet.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.