linda
  • linda
sigma (E) with 3 on top. n=0 on bottom. what does this mean??
Mathematics
chestercat
  • chestercat
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linda
  • linda
on the side on sigma, it is sin\[\pi\] over 4
anonymous
  • anonymous
\[\sum_{n=0}^{3}\sin \pi/4\] ?
anonymous
  • anonymous
Look something like that?

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linda
  • linda
theres an n before the pi symbol, but other than that its right
anonymous
  • anonymous
\[Ok so \sum_{n=0}^{3}\sin (n*\pi/4)\] So like this?
anonymous
  • anonymous
Well without the okso at the beginning.
linda
  • linda
yeah thats right
anonymous
  • anonymous
The sigma represents a summation. So if it were \[\sum_{n=0}^{3}n\] we start with n=0 plug that value in and keep adding until we reach the limit which is the top value on the sigma, 3.
anonymous
  • anonymous
So we'd have 0+1+2+3 and then stop.
linda
  • linda
so when n=0, the whole thing would equal 0 right?
anonymous
  • anonymous
Yes. You start with whatever n equals under the sigma and plug it into the function to the left of the sigma and then go to the next sequential n value and add it to that result.
linda
  • linda
so do i just start with n=0 and I get 0, then n=1 I plug it into n*pi over 4 and that equals .785 and so I add that to the zero.... then i go on to n=2 and keep adding on to the .785......
anonymous
  • anonymous
exactly!
linda
  • linda
great thanks!
anonymous
  • anonymous
good method...
anonymous
  • anonymous
Do u still have doubts @linda ?

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