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anonymous
 5 years ago
Reimann Sum Continues.
anonymous
 5 years ago
Reimann Sum Continues.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ahhh, much better lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i wrote down sum (2+3i/n)(3/n)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0good, im reviewing some notes to bring me up to speed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k can you also explain to me the point of what we are doing

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the original equation: x^3 3x can be split into easier parts x^3 and 3x we use the reimann sum formulas for (sum)x^3 and (sum)x to work these to completion

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03 lim(sum) x (3/n) is the easiest one to do, so lets start with that one :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we determined that f(x_i) = (2+3i)/n right? so if the notes are correct, and I dont see any reason to dispute them, we multiply: (2+3i)/n with 3/n

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(sum) (6/n^2 + 9i/n^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your right... I got lost there for a sec :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it says to split this one up into: (sum) 6/n+ (sum)9i/n^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, I am suuming the adding rule :) it gets us to the (sum) i formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k i split is up as you said

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(9/n^2) (sum)i is... 9 n(n+1)   n^2 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do we substitute that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.09n(n+1) 9(n+1)  =  2n^2 2n now work the other part: 6/n > 1/n (sum) 6 = (1/n)(6n) = 6 why? dunno, its just the example I got to go by :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we are at (6+(9(n+1))/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.09(n+1)   6 2n^2 6n^2 9n 9  +  +  n^2 n^2 n^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you just distributed?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lost myself too, let me redo that last part :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.09n+9   6 2n 12n 9n 9  +  +  2n 2n 2n might be better

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03 9  +  = 3 as n> inf 2 2n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lim as n goes to infinity sum =3?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03/2 ..... might be a better answer for the right side of our original equation....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I forgot the denominator of 2 :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh because 9/2n goes to 0?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep, when a fraction gets bigg on the bottom what happens? 1  becomes infinitly small 100000000000000000 it approaches zero

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0.0000000000.....00000000000000001

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea i know, sorry stupid question

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now if our f(a + i/x\) stuff was correct, then this is our right side part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we are halfway done. Should we take the cube now

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ummm...... we need to drag that 3 back over and multiply it I think :) 9/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03(3/2) = 9/2 that s right.... tell me im wrong :) i dont mind

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since its just: (sum) x^3 we can take our f^(x_1) and work it thru

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep, and I am assuming that that is correct :) otherwise we are getting good practice, but the wrong results :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0at least we have the answer so we will know

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 3/4 if you forgot

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the entire answer is 3/4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah yeah...maybe..well see :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0want me to distribute the cube?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep, cube it out so we can multiply our 3/n to it and apply the (sum) i^3 formula to it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0gonna swig some coffee..... bad mormon....BAD!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k here it is non simplified: ( 8+12i/n+12i/n18i^2/n^2+12i/n18i^2/n^218i^2/n^2+27i^3/n^3)(3/n)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0simplified loll (8+36i/n54i^2/n^2+27i^3/n^3)(3/n)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0distributing the 3/n : (24/n+108i/n^2162i^2/n^3+81i^3/n^4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0made me do all the dirty work ahhaah

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats what I get too :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now lets divvy put the "i" factors

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now we take each summation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does 24/n become

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do i just pull it out?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sum_24/n +108/n^2 sum_i 162/n^3sum_i^2 +81/n^4 sum_i^3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0muplitiply each one by the appropriate sum i^x formulas :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have to go soon, are we almost done?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0not even close :) I can do it quicker on the paper probably.... how long you got?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you attach the image after?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0aint gonna happen in 5 minutes :) I can work it out and post it here if youd like, might even figure out where I go wrong and learn something :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sounds good, that would be great. Sorry that i have to go.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for that first one i got (108n^2+108)/2n^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ill come back later to see if you posted and if you are still online, i may ask you questions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take care, you are a Hero for sure! haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hey Im back, are you there? Its kinda late but did you finish?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow amazing! You broke everything down

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You really helped me. I can't thank you enough
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