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anonymous
 5 years ago
f(x)=(x^2+10)(1x^2)
find interval of increasing, decreasing, concave up, concave down, local max and min and infection point
anonymous
 5 years ago
f(x)=(x^2+10)(1x^2) find interval of increasing, decreasing, concave up, concave down, local max and min and infection point

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did you take the derivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What did you end up with?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's not quite right by the product rule \[\frac{d}{dx}[(x^2+10)(1x^2)] \] \[=(x^2+10)\frac{d}{dx} [(1x^2)] + (1x^2) \frac{d}{dx} [(x^2+10)]\] \[=2x(x^2+10) + 2x(1x^2) = 2x(1x^2 x^2 10)\] \[=2x(2x^2 9) = 2x(2x^2 + 9)\]
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