anonymous
  • anonymous
A.Write the expression (-64)^2/3 in radical notation. B. Evaluate the radical expression. A. Write the expression in radical notation. Do not evaluate. (-64)^2/3=
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
n-e body? lol.
anonymous
  • anonymous
\[A.\text{ }(-64)^{2/3}=\sqrt[3]{-64^2} \] \[B.\text{ }(-64)^{2/3}==16 \]
anonymous
  • anonymous
.......

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anonymous
  • anonymous
Hmmmm.... it wasn't right. :(
anonymous
  • anonymous
Am I missing something?
anonymous
  • anonymous
It does say to type an exact answer, using radicals as needed
anonymous
  • anonymous
theycallmekelly, Do you want a comment from moi?
anonymous
  • anonymous
please.......
anonymous
  • anonymous
DO you know the correct answer?
anonymous
  • anonymous
...... I'm so sleepy.....
anonymous
  • anonymous
You quit writing robtobey!
anonymous
  • anonymous
With regard to problem A. I took it to mean that the fractional exponent should be converted to radical form, ie: radical sign or square root symbol. Problem B seems to request the value of Problem A. \[(-64)^2 = 4096\] The cube root of 4096 is 16. \[4096^{1/3} = \sqrt[3]{4096} = 16\] By convention: \[\sqrt[3]{x^2} = x^{\frac{2}{3}} \]
anonymous
  • anonymous
So A would be 4096?
anonymous
  • anonymous
...........
anonymous
  • anonymous
No. Refer to the second version of A. It says not to evaluate A. Only show the symbolic form of the expression, not the number value of the expression. The whole thing seems to be a test of whether or not you under stand how to handle fractional exponents. Google "fractional exponents math' and I'm sure you will find some excellent presentations regarding fractional exponents.
anonymous
  • anonymous
Lol, so what is A then?
anonymous
  • anonymous
The answer to A is: \[\sqrt[3]{(-64)^2}\] That's about all I can do with this problem.
anonymous
  • anonymous
Yes! Lol, that part was right!
anonymous
  • anonymous
Any idea on B?
anonymous
  • anonymous
The answer is 16 as I tried to explain in my second response to you tonight.

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