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anonymous

  • 5 years ago

A.Write the expression (-64)^2/3 in radical notation. B. Evaluate the radical expression. A. Write the expression in radical notation. Do not evaluate. (-64)^2/3=

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  1. anonymous
    • 5 years ago
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    n-e body? lol.

  2. anonymous
    • 5 years ago
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    \[A.\text{ }(-64)^{2/3}=\sqrt[3]{-64^2} \] \[B.\text{ }(-64)^{2/3}==16 \]

  3. anonymous
    • 5 years ago
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    .......

  4. anonymous
    • 5 years ago
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    Hmmmm.... it wasn't right. :(

  5. anonymous
    • 5 years ago
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    Am I missing something?

  6. anonymous
    • 5 years ago
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    It does say to type an exact answer, using radicals as needed

  7. anonymous
    • 5 years ago
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    theycallmekelly, Do you want a comment from moi?

  8. anonymous
    • 5 years ago
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    please.......

  9. anonymous
    • 5 years ago
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    DO you know the correct answer?

  10. anonymous
    • 5 years ago
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    ...... I'm so sleepy.....

  11. anonymous
    • 5 years ago
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    You quit writing robtobey!

  12. anonymous
    • 5 years ago
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    With regard to problem A. I took it to mean that the fractional exponent should be converted to radical form, ie: radical sign or square root symbol. Problem B seems to request the value of Problem A. \[(-64)^2 = 4096\] The cube root of 4096 is 16. \[4096^{1/3} = \sqrt[3]{4096} = 16\] By convention: \[\sqrt[3]{x^2} = x^{\frac{2}{3}} \]

  13. anonymous
    • 5 years ago
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    So A would be 4096?

  14. anonymous
    • 5 years ago
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    ...........

  15. anonymous
    • 5 years ago
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    No. Refer to the second version of A. It says not to evaluate A. Only show the symbolic form of the expression, not the number value of the expression. The whole thing seems to be a test of whether or not you under stand how to handle fractional exponents. Google "fractional exponents math' and I'm sure you will find some excellent presentations regarding fractional exponents.

  16. anonymous
    • 5 years ago
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    Lol, so what is A then?

  17. anonymous
    • 5 years ago
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    The answer to A is: \[\sqrt[3]{(-64)^2}\] That's about all I can do with this problem.

  18. anonymous
    • 5 years ago
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    Yes! Lol, that part was right!

  19. anonymous
    • 5 years ago
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    Any idea on B?

  20. anonymous
    • 5 years ago
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    The answer is 16 as I tried to explain in my second response to you tonight.

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