anonymous
  • anonymous
if f(x)=(x+1)(1-x^2), evaluate f(a+3)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
some help me
anonymous
  • anonymous
Plug in (a+3) for every value of x in f(x).
anonymous
  • anonymous
uh huh i got =((a+3)+1)(1-(a+3)^2) dont know what to do after that

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anonymous
  • anonymous
\[f(a+3) = (a+3+1)(1-(a+3)^2)\] just like pjschlotter said.
anonymous
  • anonymous
Got it!
anonymous
  • anonymous
Solve it like: (a+3+1) = (a+4) (a+4) (1-(a^2 +6a + 9)) (a+4) (-a^2 -6a -8)
anonymous
  • anonymous
You can also multiply (a+4) for the rest, but I don't think it's necessary... this form is clearer.
anonymous
  • anonymous
thank you where is the 6a from?
anonymous
  • anonymous
It's from the development of (a+3)^2, right? (b+c)^2 = b^2 + 2.b.c + c^2 So, (a+3)^2 = a^2 + 2.a.3 + 3^2 = a^2 + 6a + 3^2
anonymous
  • anonymous
ok kinda got it so if the number is 6 instead of 3 then it would be 12a instead of 6a correct?
anonymous
  • anonymous
Correct!
anonymous
  • anonymous
so is the solution -12a^2-32a-32
anonymous
  • anonymous
It's (a+4) (-a^2 -6a -8), as I said!
anonymous
  • anonymous
oh i though you have to combine them. but thanks alot how do i become a fan?
anonymous
  • anonymous
can you help me with another problem?
anonymous
  • anonymous
Of course, just send it. :)
anonymous
  • anonymous
Erm, actually, I gotta go sleep. lol Class tomorrow. See ya.

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