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anonymous

  • 5 years ago

can any help me with the deriv. of 16w+6((310/w))+3w???? and the critical ppoints/// i cant get a right answer

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  1. anonymous
    • 5 years ago
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    \[16w+6(310/w)+3w\] right?

  2. anonymous
    • 5 years ago
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    yea

  3. dumbcow
    • 5 years ago
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    first add like terms then find derivative of each term using the power rule

  4. anonymous
    • 5 years ago
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    would i multiply 6by 310?

  5. dumbcow
    • 5 years ago
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    yes

  6. dumbcow
    • 5 years ago
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    remember 1/w = w^-1

  7. anonymous
    • 5 years ago
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    so i got the function to be derived... (1860/w)+19w?,,

  8. dumbcow
    • 5 years ago
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    correct

  9. anonymous
    • 5 years ago
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    isnt that the quotient rule then ? i got (1860/w^2)+19

  10. dumbcow
    • 5 years ago
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    you could use the quotient rule, however be careful about the sign it should be -(1860/w^2) +19 (f/g)' = f'g - g'f/g^2

  11. dumbcow
    • 5 years ago
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    now set it equal to zero and solve for w

  12. dumbcow
    • 5 years ago
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    you should get w^2 = 1860/19

  13. anonymous
    • 5 years ago
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    right igot that ...

  14. anonymous
    • 5 years ago
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    +_9.894176916

  15. dumbcow
    • 5 years ago
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    ok good those are your critical points

  16. anonymous
    • 5 years ago
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    ok thanks you lots...

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