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(- oo, oo)

Domain is looking for numbers where the function is discontinuous.

it is continuoues everywhere so its from negative infinity to infinity

Thank you!

oo yeah gotcha, i was giving a reason to my answer

Alright, no worries.

you guys are cool! very helpful i think i have a harder one

And that is?

f(x)=x+squartroot x^2+1

cant figure out how to do the squartroot symbol

Here you would check \[\sqrt{x^2+1}\] and well what do you find out?

hmm what if its sqrt root of x^2-1 instead. will it be same

Nope.

x cant be 1

Not quite. If x=1 it's still valid.

pj has it right

hmm still not understanding

If you plug zero in for x in \[\sqrt{x^2-1}\] you get \[\sqrt{-1}\] which is imaginary and not good.

oh ok that wat you meant

thanks

Make sense?