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Okay, I really appreciate your time. It clears things up a great deal for me.

oo your welcome.

I'm out for the night. I'm sure I'll be back in the future.

Okay, I'm back. Yes, that is the expression.

The expression simplifies to:
\[\frac{2+x}{1+x}\]
When x=-1 in the denominator, you have division by zero which is a no no.
There seems to be a root at x=-2
Refer to the plot attachment.

Sorry. I guess I'll have to google "removable discontinuity math"