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- anonymous

vertex and roots of f(t)-16t^2+70t+4

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- anonymous

vertex and roots of f(t)-16t^2+70t+4

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- anonymous

f(t)=-16^2+70t+4
sorry

- dumbcow

f'(t) should be -32t + 70
to find vertex set equal to 0

- anonymous

ahhh sorry it's -16t^2+70+4
we're supposed to find -b/2a to find t, then plug that in the find vertex, and then the roots i came up with were 35+or-sqrt1097 divided by 16

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- dumbcow

sorry about that, vertex looks good check the sqare root part in the quadratic formula

- dumbcow

i get 35 +- sqrt(1289) divided by 16

- anonymous

b^2=35*35=1225
4ac=4(8)(4)=128
1225-128=1097? I think thats right, its asking for x-intercepts to graph it. how do i graph this?

- dumbcow

redo the problem, this time looking closely at the signs.

- anonymous

-4 got it. thank you!!!!!!!

- dumbcow

4ac = 4(-8)(2)

- anonymous

ooooh yeah. haha. thank you so much. but that means there are no x-intercepts right?

- dumbcow

ok so now x = (35+- sqrt(1289))/16
those two x values are your x-intercepts
graph them as 2 points. (x1,0) and (x2,0)

- dumbcow

get a graphing calculator to check your answers

- anonymous

but you can't graph that what we got for x

- dumbcow

do you mean on a graphing calculator or by hand

- anonymous

so like the question is about baseball and how long it takes for the ball to hit the ground and after how many seconds. when i graph it, (0,4) is the y-int, (35/16, 1289/16) is the vertex (or the highest point the ball gets to) and then to figure out when the ball lands on the ground would be the x-int

- dumbcow

the x-int would be one of the answers derived from the quadratic formula.

- anonymous

even if its like never ending full of decimals? would i just round it up?

- dumbcow

yes round to two or three decimal places depending on what your teacher prefers.

- anonymous

oh ok. i think i got it this time then. thanks for all your help! =]

- dumbcow

you're welcome. next time you ask for help it would be beneficial to state the entire problem not just the part you're stuck on. it gives me context. Thanks!

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