Let r be the region bounded by the graphs of y= sqrt(x) and y=x/2.?
a)Find the area of R
b)the region R is the base of a solid. for this solid, the criss sections perpendicular to the x-axis are squares. find the volume of this solid.
c)write, but do not evaluate, an integral expression for the volume for this solid generated when R is rotated about the horizontal line y=2.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
are you supposed to be graphing and counting blocks or finding the exact area under the curve using shell/disk method?
well y=sqr(x) is a parabola and y=x/2 is a line that runs through it right? so which do you use, shell or disk
Not the answer you are looking for? Search for more explanations.
I think it is a disc.
in this particular situation, you could use either, its really whatever you feel like but in some senarios you have to split it up into two sections depending on the method so you just pick the easiest way.