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anonymous

  • 5 years ago

Let r be the region bounded by the graphs of y= sqrt(x) and y=x/2.? a)Find the area of R b)the region R is the base of a solid. for this solid, the criss sections perpendicular to the x-axis are squares. find the volume of this solid. c)write, but do not evaluate, an integral expression for the volume for this solid generated when R is rotated about the horizontal line y=2.

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  1. anonymous
    • 5 years ago
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    are you supposed to be graphing and counting blocks or finding the exact area under the curve using shell/disk method?

  2. anonymous
    • 5 years ago
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    shell/disk method

  3. anonymous
    • 5 years ago
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    well y=sqr(x) is a parabola and y=x/2 is a line that runs through it right? so which do you use, shell or disk

  4. anonymous
    • 5 years ago
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    I think it is a disc.

  5. anonymous
    • 5 years ago
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    in this particular situation, you could use either, its really whatever you feel like but in some senarios you have to split it up into two sections depending on the method so you just pick the easiest way.

  6. anonymous
    • 5 years ago
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    hmm...okay

  7. anonymous
    • 5 years ago
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    do you know how to find your limits?

  8. anonymous
    • 5 years ago
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    I think I got it now. Thanks for the help.

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