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anonymous

  • 5 years ago

I have a problem where I must find the Cartesian equation for: x=t^2 y=4+3t into x=Ay^2+By+C I have found C, but need help in finding the values for A and B

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  1. anonymous
    • 5 years ago
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    it seems you are either missing some info here or im a bit more rusty on geometry than i thought, how exactly did you find C?

  2. anonymous
    • 5 years ago
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    I came up with t^2=A(4+3t)^2+B(4+3t)+C

  3. anonymous
    • 5 years ago
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    but i'm still kind of confused as to how I even got it ha

  4. anonymous
    • 5 years ago
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    it's the correct problem i checked

  5. anonymous
    • 5 years ago
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    yeah, you have 3 variables there and no way to eliminate any of them, so unless your proff gave you some format to put it into and then from that you know the points your trying to find?

  6. anonymous
    • 5 years ago
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    i mean the way to eliminate them is to use the t value and then deal with that bottom equation

  7. anonymous
    • 5 years ago
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    so lik eeither put everything in terms of x or y

  8. anonymous
    • 5 years ago
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    right but you can only ever solve the variables in terms of the other variables, meaning you can find A as a function of B and C, B(A,C) and C(A,B)

  9. anonymous
    • 5 years ago
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    yes i know that's why i need to find a way out by plugging in constants on both sides of the equation that make A or B go to zero in order to solve for the variables

  10. anonymous
    • 5 years ago
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    ahh, right. and then you just do the same thing to find A and B i think, set the ones your not finding to 0

  11. anonymous
    • 5 years ago
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    see i don't know how to do the rest i'm really cracked out and can't thinka nymore ha

  12. anonymous
    • 5 years ago
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    honestly you should confinr that with someone else too though, its been a while since iv done a problem like this

  13. anonymous
    • 5 years ago
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    if your finding A you just set B and C to 0 because they are intercepts, right?

  14. anonymous
    • 5 years ago
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    well i'll know if it's right because i have to type my answers into a computer system that will tell me if it's correct or not

  15. anonymous
    • 5 years ago
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    unlimited trials

  16. anonymous
    • 5 years ago
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    here we go: http://www.personal.kent.edu/~rmuhamma/Algorithms/MyAlgorithms/parabola.htm

  17. anonymous
    • 5 years ago
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    so you have a polynomial function of the 2nd degree which is a quadradic

  18. anonymous
    • 5 years ago
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    ok

  19. anonymous
    • 5 years ago
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    question where do u go to school?

  20. anonymous
    • 5 years ago
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    this is a trickey little bastard, you have to change the form of the original equation. see If b = 0, the quadratic function has the form f(x) = ax2 + c. so what i think you have to do, is noting those derived equations and plugging in 0 to the other variables you get some new equations which then allow you to solve for the others by plugging them into eachother. lemme keep reading

  21. anonymous
    • 5 years ago
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    ughhh it sucks!! i haven't slept in two days fml

  22. anonymous
    • 5 years ago
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    lol its been too long, i dont understand what that website is saying...

  23. anonymous
    • 5 years ago
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    ok let me think about this for a minute and see if i can figure it out

  24. anonymous
    • 5 years ago
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    do you work for this website or something or are you a student ? i don't really understand this website ha

  25. anonymous
    • 5 years ago
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    nah im just a student

  26. anonymous
    • 5 years ago
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    oh where?

  27. anonymous
    • 5 years ago
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    Rochester Institute of Technology

  28. anonymous
    • 5 years ago
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    small fluttering world

  29. anonymous
    • 5 years ago
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    i go to u of r

  30. anonymous
    • 5 years ago
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    no way hahaha thats crazy. i was about to say dont even lie to me that you go to rit, your sn has "girl" in it

  31. anonymous
    • 5 years ago
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    haha yea i don't go there a lot, ha or ever for that matter, but i have some friends from high school there

  32. anonymous
    • 5 years ago
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    oh your from around here, thats cool. what year are you?

  33. anonymous
    • 5 years ago
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    i'm a junior

  34. anonymous
    • 5 years ago
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    lol im a 3rd year too. i know a couple kids who went to school around here but i dont know what schools or anything cause im from boston

  35. anonymous
    • 5 years ago
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    bosston, i lived there this summer ha, well i lived in watertown

  36. anonymous
    • 5 years ago
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    literallrally everyone from u of r is from boston

  37. anonymous
    • 5 years ago
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    i say boston its really the southern NH border but i'v driven through watertown more than once. and yeah it seems like that here too, i know tons of people from the boston area

  38. anonymous
    • 5 years ago
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    im still in awe that at 2am out of 23 online people i found someone thats currently within a 10 mile radius of me

  39. anonymous
    • 5 years ago
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    i am too, it's just too weird

  40. anonymous
    • 5 years ago
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    what do you major in ?

  41. anonymous
    • 5 years ago
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    computer engineering technology, you?

  42. anonymous
    • 5 years ago
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    ha sounds intense, i'm doing business econ and psych

  43. anonymous
    • 5 years ago
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    haha im concentrating in psych, too weird

  44. anonymous
    • 5 years ago
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    haha oh the weird realms of the internet

  45. anonymous
    • 5 years ago
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    its got to be less coincidental than were making it out to be. were in a pretty tech-savvy part of the english speaking world. but still thats the whole northern east coast...

  46. anonymous
    • 5 years ago
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    how did you find this site?

  47. anonymous
    • 5 years ago
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    haha idk i was just wearching for help things and it came up

  48. anonymous
    • 5 years ago
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    why do you help random people with math?

  49. anonymous
    • 5 years ago
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    honestly i dont really know

  50. anonymous
    • 5 years ago
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    i kinda stumbled here like 2 days ago and got a kick out of helping people out with their math, most of the stuff on here is low level calc or easier so its not so bad

  51. anonymous
    • 5 years ago
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    guess i got sick of facebook and this was another way to procrastinate?

  52. anonymous
    • 5 years ago
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    i guess that's not a bad way to procrastinate, bettering the world's math skills

  53. anonymous
    • 5 years ago
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    haha, yeah doing other people's homework is fun but doing my own is agonizing, go figure

  54. anonymous
    • 5 years ago
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    ha

  55. anonymous
    • 5 years ago
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    what class is your parabola thinger from? i dont remember having to do this stuff

  56. anonymous
    • 5 years ago
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    third semester of calc

  57. anonymous
    • 5 years ago
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    shows how much i learned in calc...

  58. anonymous
    • 5 years ago
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    but it's something i learned a long time ago, i just don't remember it

  59. anonymous
    • 5 years ago
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    don't worry though, i have the rochester minions working on it

  60. anonymous
    • 5 years ago
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    the rochester minions eigh?

  61. anonymous
    • 5 years ago
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    yes

  62. anonymous
    • 5 years ago
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    you should prolly let me know how to go about contacting these minions. could be helpful for diff eq

  63. anonymous
    • 5 years ago
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    haha, you literally just walk around u of r campus, they're around, sometimes you have to look in the stacks or the depths of the librar but there's always a guarantee you'll find one

  64. anonymous
    • 5 years ago
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    haha, even at 2 am. that seems sketchy, especially the library part, whats a library?

  65. anonymous
    • 5 years ago
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    the minions are having trouble with it too, darn

  66. anonymous
    • 5 years ago
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    tell your professor that its impossible. ill see if my roomate knows how to do it

  67. anonymous
    • 5 years ago
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    ok it's just it's due tomorrow morning at 6am ick

  68. anonymous
    • 5 years ago
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    haha people keep looking at this question and then leaving

  69. anonymous
    • 5 years ago
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    theres 3 rit kids in here working on your silly parabola

  70. anonymous
    • 5 years ago
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    you said you have infinite number of trys?

  71. anonymous
    • 5 years ago
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    \[y=4+3\sqrt{x}\]

  72. anonymous
    • 5 years ago
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    give that a go

  73. anonymous
    • 5 years ago
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    i'll try it

  74. anonymous
    • 5 years ago
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    idk how long this website will wokrk though, its slowing my comp down a lot

  75. anonymous
    • 5 years ago
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    i got A it's 1/9, idk if that will help find B

  76. anonymous
    • 5 years ago
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    lol i have no idea how you got that or what it means. anyways im going to go sleep or eat or something, facebook me (Tim Heebs) you should come to some parties and bring friends. god knows RIT needs help with the ratio at parties haha

  77. anonymous
    • 5 years ago
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    haha yea, your name already showed up when i was worried about the problem, and yea us girls here sometimes want to go to some RIT parties, that would be cool

  78. anonymous
    • 5 years ago
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    sounds good, ttyl then. good luck with your calc

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