I have a problem where I must find the Cartesian equation for: x=t^2 y=4+3t into x=Ay^2+By+C I have found C, but need help in finding the values for A and B

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I have a problem where I must find the Cartesian equation for: x=t^2 y=4+3t into x=Ay^2+By+C I have found C, but need help in finding the values for A and B

Mathematics
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it seems you are either missing some info here or im a bit more rusty on geometry than i thought, how exactly did you find C?
I came up with t^2=A(4+3t)^2+B(4+3t)+C
but i'm still kind of confused as to how I even got it ha

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it's the correct problem i checked
yeah, you have 3 variables there and no way to eliminate any of them, so unless your proff gave you some format to put it into and then from that you know the points your trying to find?
i mean the way to eliminate them is to use the t value and then deal with that bottom equation
so lik eeither put everything in terms of x or y
right but you can only ever solve the variables in terms of the other variables, meaning you can find A as a function of B and C, B(A,C) and C(A,B)
yes i know that's why i need to find a way out by plugging in constants on both sides of the equation that make A or B go to zero in order to solve for the variables
ahh, right. and then you just do the same thing to find A and B i think, set the ones your not finding to 0
see i don't know how to do the rest i'm really cracked out and can't thinka nymore ha
honestly you should confinr that with someone else too though, its been a while since iv done a problem like this
if your finding A you just set B and C to 0 because they are intercepts, right?
well i'll know if it's right because i have to type my answers into a computer system that will tell me if it's correct or not
unlimited trials
here we go: http://www.personal.kent.edu/~rmuhamma/Algorithms/MyAlgorithms/parabola.htm
so you have a polynomial function of the 2nd degree which is a quadradic
ok
question where do u go to school?
this is a trickey little bastard, you have to change the form of the original equation. see If b = 0, the quadratic function has the form f(x) = ax2 + c. so what i think you have to do, is noting those derived equations and plugging in 0 to the other variables you get some new equations which then allow you to solve for the others by plugging them into eachother. lemme keep reading
ughhh it sucks!! i haven't slept in two days fml
lol its been too long, i dont understand what that website is saying...
ok let me think about this for a minute and see if i can figure it out
do you work for this website or something or are you a student ? i don't really understand this website ha
nah im just a student
oh where?
Rochester Institute of Technology
small fluttering world
i go to u of r
no way hahaha thats crazy. i was about to say dont even lie to me that you go to rit, your sn has "girl" in it
haha yea i don't go there a lot, ha or ever for that matter, but i have some friends from high school there
oh your from around here, thats cool. what year are you?
i'm a junior
lol im a 3rd year too. i know a couple kids who went to school around here but i dont know what schools or anything cause im from boston
bosston, i lived there this summer ha, well i lived in watertown
literallrally everyone from u of r is from boston
i say boston its really the southern NH border but i'v driven through watertown more than once. and yeah it seems like that here too, i know tons of people from the boston area
im still in awe that at 2am out of 23 online people i found someone thats currently within a 10 mile radius of me
i am too, it's just too weird
what do you major in ?
computer engineering technology, you?
ha sounds intense, i'm doing business econ and psych
haha im concentrating in psych, too weird
haha oh the weird realms of the internet
its got to be less coincidental than were making it out to be. were in a pretty tech-savvy part of the english speaking world. but still thats the whole northern east coast...
how did you find this site?
haha idk i was just wearching for help things and it came up
why do you help random people with math?
honestly i dont really know
i kinda stumbled here like 2 days ago and got a kick out of helping people out with their math, most of the stuff on here is low level calc or easier so its not so bad
guess i got sick of facebook and this was another way to procrastinate?
i guess that's not a bad way to procrastinate, bettering the world's math skills
haha, yeah doing other people's homework is fun but doing my own is agonizing, go figure
ha
what class is your parabola thinger from? i dont remember having to do this stuff
third semester of calc
shows how much i learned in calc...
but it's something i learned a long time ago, i just don't remember it
don't worry though, i have the rochester minions working on it
the rochester minions eigh?
yes
you should prolly let me know how to go about contacting these minions. could be helpful for diff eq
haha, you literally just walk around u of r campus, they're around, sometimes you have to look in the stacks or the depths of the librar but there's always a guarantee you'll find one
haha, even at 2 am. that seems sketchy, especially the library part, whats a library?
the minions are having trouble with it too, darn
tell your professor that its impossible. ill see if my roomate knows how to do it
ok it's just it's due tomorrow morning at 6am ick
haha people keep looking at this question and then leaving
theres 3 rit kids in here working on your silly parabola
you said you have infinite number of trys?
\[y=4+3\sqrt{x}\]
give that a go
i'll try it
idk how long this website will wokrk though, its slowing my comp down a lot
i got A it's 1/9, idk if that will help find B
lol i have no idea how you got that or what it means. anyways im going to go sleep or eat or something, facebook me (Tim Heebs) you should come to some parties and bring friends. god knows RIT needs help with the ratio at parties haha
haha yea, your name already showed up when i was worried about the problem, and yea us girls here sometimes want to go to some RIT parties, that would be cool
sounds good, ttyl then. good luck with your calc

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