A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
http://locker.palcs.org/~jbaskwill/pc/54practice.pdf
need help with 110 except #2
anonymous
 5 years ago
http://locker.palcs.org/~jbaskwill/pc/54practice.pdf need help with 110 except #2

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01) cosx=sin2x cosx = 2sinx cosx 0 = 2sinx cosx  cosx 0 = cosx(2sinx1) 2sinx1 = 0 OR cosx = 0 2sinx=1 x = 90, 270 sinx =1/2 sinx=sin30 or sinx=sin(18030) x =30 or x=150 answer : C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03) sin2x=sinx 2sinx cosx = sinx 2sinxcosx + sinx = 0 sinx(2cosx +1) = 0 2cosx +1=0 OR sinx=0 2cosx =1 x = 0, 180 cosx = 1/2 cosx = cos(18060) OR cosx = cos (180+60) x = 120 x = 240 the value of cosx will be negative if it's located in quadrant 2 and 3 answer : A

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04) 2cosx + sin2x = 0 this isn't much different number 1 and 3 try to do it by yourself :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0typo, i mean : number 4 isnt much different with number 1 and 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.09) \[ \cos x = \sin (x/2)\] \[12\sin ^{2}(x/2) = \sin(x/2)\] \[2\sin ^{2}(x/2) + \sin(x/2)  1 = 0\] (2sin(x/2)  1)(sin(x/2)+1) = 0 sin(x/2) = 1/2 or sin(x/2) = 1 sin(x/2) = sin 30 sin(x/2) = sin270 x/2 = 30 x/2 = 270 x= 60 x = 540 > this is out of interval OR sin(x/2) = 150 x=300 answer : A
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.