anonymous
  • anonymous
A milling company wants to mix alfalfa, which contains 20% protein and wheat mids, which contains 15% protein to make cattle feed. The milling company wants to make 1000 pounds of cattle feed that contains 17% protein. How many pounds of alfalfa and how many pounds of wheat mids must be used?
Mathematics
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anonymous
  • anonymous
A milling company wants to mix alfalfa, which contains 20% protein and wheat mids, which contains 15% protein to make cattle feed. The milling company wants to make 1000 pounds of cattle feed that contains 17% protein. How many pounds of alfalfa and how many pounds of wheat mids must be used?
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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amistre64
  • amistre64
(amount) times (percentage) is the basic unit for this problem
amistre64
  • amistre64
we have an amount of "a" at 20%. And we have an amount "w" at 15%. when we add these amount together they sould equal 1000 lbs total and have 17% protien.
amistre64
  • amistre64
a + w = 1000; this means that: a = 1000-w a(.20) + w(.15) = 1000(.17) (1000-w)(.20) + .15w = 170 200 - .20w + .15w = 170 -.05w = -30 .05w = 30 w = 600 lbs a + 600 = 1000; so a = 400lbs lets see if it works..... 400(.20) + 600(.15) = 1000(.17) 80 + 90 = 170 170 = 170 ...its good :)

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