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anonymous

  • 5 years ago

2x^2+4x-3 in the form of f(x)=a(x-h)^2+k

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  1. nowhereman
    • 5 years ago
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    Those two forms are equal if the coefficients are the same. So look at \[2x^2 + 4x - 3 = ax^2 - 2ahx-h^2+k\] identify the coefficients and solve for a, h and k.

  2. radar
    • 5 years ago
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    I am treading on dangerous ground here. When i substitute the coefficients I come up with a=2, h=1 and k=-3\[f(x)=2(x-1)^{2}-3\] Not 100% sure about it though. What have you come up with?

  3. radar
    • 5 years ago
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    the k is wrong it has to be -5

  4. radar
    • 5 years ago
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    Hopefully nowhereman will bail me out of this quagmire!

  5. nowhereman
    • 5 years ago
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    To finish this, you get (sorry should be +a in front of h^2 up there): \[2 = a,\quad 4 = -2ah,\quad -3 = ah^2 + k\] which lead to \[ a = 2,\quad h = -1,\quad k = -5\] so that you have \[2x^2 + 4x - 3 = 2(x+1)^2-5\]

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