## anonymous 5 years ago 2x^2+4x-3 in the form of f(x)=a(x-h)^2+k

1. nowhereman

Those two forms are equal if the coefficients are the same. So look at $2x^2 + 4x - 3 = ax^2 - 2ahx-h^2+k$ identify the coefficients and solve for a, h and k.

I am treading on dangerous ground here. When i substitute the coefficients I come up with a=2, h=1 and k=-3$f(x)=2(x-1)^{2}-3$ Not 100% sure about it though. What have you come up with?

the k is wrong it has to be -5

Hopefully nowhereman will bail me out of this quagmire!

5. nowhereman

To finish this, you get (sorry should be +a in front of h^2 up there): $2 = a,\quad 4 = -2ah,\quad -3 = ah^2 + k$ which lead to $a = 2,\quad h = -1,\quad k = -5$ so that you have $2x^2 + 4x - 3 = 2(x+1)^2-5$