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anonymous

  • 5 years ago

find the domain of the function f(X) = ln(2-x)

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  1. anonymous
    • 5 years ago
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    domain of this function would be x<=2 since log is not defined for negative values

  2. anonymous
    • 5 years ago
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    so it is (- infinity, 2]

  3. anonymous
    • 5 years ago
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    got it jsy? or u need more clarification? :):)

  4. anonymous
    • 5 years ago
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    sry *jay

  5. anonymous
    • 5 years ago
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    Are you there???? @jay

  6. amistre64
    • 5 years ago
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    ln is not define for zero either....when does ln(x) = 0?

  7. anonymous
    • 5 years ago
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    log 0 = 1 am i right?

  8. anonymous
    • 5 years ago
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    if its so, then the answer is (-infinity, 2)

  9. amistre64
    • 5 years ago
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    no...sorry :) thats better.. think of it this way. the log points to an exponent: log2(8) = 3 the exponent is "3" the base is to "2" 2^3 = 8 now tell me.... 2^? = 0 ??

  10. amistre64
    • 5 years ago
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    log2(0) = ?

  11. anonymous
    • 5 years ago
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    then my second option is correct? isn't it? and not the first one...

  12. amistre64
    • 5 years ago
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    (-inf,2) is correct :)

  13. anonymous
    • 5 years ago
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    hmm.... yay amistre:)

  14. anonymous
    • 5 years ago
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    i think jay is not here

  15. amistre64
    • 5 years ago
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    jay was just the catalyst.... math goes on without him lol

  16. anonymous
    • 5 years ago
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    :)but i think this shud help him

  17. anonymous
    • 5 years ago
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    i definitely see that as an option thank u so much

  18. anonymous
    • 5 years ago
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    you 're welcome:) any more questions??

  19. anonymous
    • 5 years ago
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    \[2-x \ge0\]\[x \le 2\] hence the domain is \[[-\infty, 2)\]

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spraguer (Moderator)
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