anonymous
  • anonymous
Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
alex??
anonymous
  • anonymous
\[2-11x^2-8x+6x^2\]
anonymous
  • anonymous
5x^2+8x-2=0 ......... polynomial of second degree or a quadratic equation:)

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More answers

anonymous
  • anonymous
dang ur fast... think you can do some more????
anonymous
  • anonymous
i'll try...hey r u alex??
amistre64
  • amistre64
lol.... think can count real quick like ;)
anonymous
  • anonymous
:D
anonymous
  • anonymous
no alex... jordan
amistre64
  • amistre64
i think thats a fake name.... i know a river named jordan :)
anonymous
  • anonymous
ohh im sry jordan...neva mind...ask the question..lecce if i acn answer...as i have to rush in 5 mins...so be quick
amistre64
  • amistre64
my name is ...ummm..they call me "tater" ...sorry, bluecollar stuff
anonymous
  • anonymous
but i know ur name
anonymous
  • anonymous
4g-g^3+3g^2-2
anonymous
  • anonymous
u lie u are not ron white
amistre64
  • amistre64
LOL gotta love it :)
anonymous
  • anonymous
g^3-3g^2-4g+2=0 poly of 3rd degree:):)
amistre64
  • amistre64
its a cubic...get it right!!
anonymous
  • anonymous
yupp:) i am quick at these:D
anonymous
  • anonymous
got it jordan?
amistre64
  • amistre64
uhoh...theyre coming to take me away hehe....theyre coming to take me away!!!!!!! Ciao yall :)
anonymous
  • anonymous
6x^8y^5
anonymous
  • anonymous
ciao mistretta :)
anonymous
  • anonymous
u may be quick at these but i fail at these
anonymous
  • anonymous
haha...no worries:) i am here to help u jordan...it is a mixed poly of 8th & 5th degree
anonymous
  • anonymous
well on the thingymabober. 5 and 8 arw seperate answers
anonymous
  • anonymous
now i gotta go...bye all...cu the next time:) probably next friday:))..jones typing?? be really quick plz
anonymous
  • anonymous
bye all..hope i helped u jordan:)
anonymous
  • anonymous
ok see ya
anonymous
  • anonymous
c ya:) al the best..n yeah bye to u too oktal
anonymous
  • anonymous
can any1 else help??

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