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anonymous
 5 years ago
Use the graph to determine each limite, if any. Graph:
http://i55.tinypic.com/20uewcn.jpg
i) lim (x > 2) f(x)
ii) lim (x > 2+) f(x)
iii) lim (x > 2) f(x)
iv) lim (x > 0) f(x)
v) lim (x > 0+) f(x)
vi) lim (x > 0) f(x)
For a:
i) ∞, ii) ∞, iii) doesn't exist, iv) doesn't exist, v) 0, v) doesn't exist
For b:
i) 0, ii) ∞, iii) doesn't exist, iv) doesn't exist, v) ∞, vi) doesn't exist
Is that correct?
anonymous
 5 years ago
Use the graph to determine each limite, if any. Graph: http://i55.tinypic.com/20uewcn.jpg i) lim (x > 2) f(x) ii) lim (x > 2+) f(x) iii) lim (x > 2) f(x) iv) lim (x > 0) f(x) v) lim (x > 0+) f(x) vi) lim (x > 0) f(x) For a: i) ∞, ii) ∞, iii) doesn't exist, iv) doesn't exist, v) 0, v) doesn't exist For b: i) 0, ii) ∞, iii) doesn't exist, iv) doesn't exist, v) ∞, vi) doesn't exist Is that correct?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, what do you need help with specifically?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need to know if my answers are corrects, pls

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey, sorry, dipped out, back now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so there is a vertical asymptot at 2 for (A)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A)  i, ii, iii are definitely good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, so at 0 there is no value

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got it! Now, my main troubles are the letters iv, v, vi.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, i'm having trouble with A...let's move to some of B

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in B, it appears that the limit it one for i, ii, iii, despite it not being continuous i believe the limit exists

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the function is defined at x = 0, y=1 there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right! Now i can go on. Thanks man!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, sorry, not the most helpful, but a start...maybe someone else can clear the rest up
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