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anonymous

  • 5 years ago

Use the graph to determine each limite, if any. Graph: http://i55.tinypic.com/20uewcn.jpg i) lim (x -> 2-) f(x) ii) lim (x -> 2+) f(x) iii) lim (x -> 2) f(x) iv) lim (x -> 0-) f(x) v) lim (x -> 0+) f(x) vi) lim (x -> 0) f(x) For a: i) -∞, ii) ∞, iii) doesn't exist, iv) doesn't exist, v) 0, v) doesn't exist For b: i) 0, ii) ∞, iii) doesn't exist, iv) doesn't exist, v) ∞, vi) doesn't exist Is that correct?

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  1. anonymous
    • 5 years ago
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    here is your graph

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  2. anonymous
    • 5 years ago
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    ok, what do you need help with specifically?

  3. anonymous
    • 5 years ago
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    I need to know if my answers are corrects, pls

  4. anonymous
    • 5 years ago
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    hey, sorry, dipped out, back now

  5. anonymous
    • 5 years ago
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    ok, so there is a vertical asymptot at 2 for (A)

  6. anonymous
    • 5 years ago
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    x=2

  7. anonymous
    • 5 years ago
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    A) - i, ii, iii are definitely good

  8. anonymous
    • 5 years ago
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    yeah, so at 0 there is no value

  9. anonymous
    • 5 years ago
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    it's an open circle

  10. anonymous
    • 5 years ago
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    I got it! Now, my main troubles are the letters iv, v, vi.

  11. anonymous
    • 5 years ago
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    sorry, i'm having trouble with A...let's move to some of B

  12. anonymous
    • 5 years ago
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    in B, it appears that the limit it one for i, ii, iii, despite it not being continuous i believe the limit exists

  13. anonymous
    • 5 years ago
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    sorry, -1

  14. anonymous
    • 5 years ago
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    and the function is defined at x = 0, y=1 there

  15. anonymous
    • 5 years ago
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    Right! Now i can go on. Thanks man!

  16. anonymous
    • 5 years ago
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    ok, sorry, not the most helpful, but a start...maybe someone else can clear the rest up

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spraguer (Moderator)
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