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plug, then chug.
what you mean plug than chug
Replace x with 0 and evaluate the function. Then do the same thing for -1 and 2. If you are sufficiently skilled in math to be evaluating powers (\(x^2\)) you should be sufficiently skilled in substituting values for a variable. Did you have a specific question on how to arrive at an answer here?
Yes I have never done algebra this is my first year in algebra thats y I said how do you plug and chug
f(0) means take 0 and replace x with it. Then evaluate the function to find the result.
\[3(0)^2-3(0) = 3*0 - 3*0 = 0-0 = 0\]
Now do the same thing for -1 and 2.
ok so I use the 0 with the -1 and 2
No. You use the function with -1 and 2.
I am so sry I am still confused, I guess I just skip over it
No, don't skip over it. Figure out what is confusing to you. Is English your native language, cause it's not clear to me which part of my explanation doesn't make sense. \[f(x) = 3x^2-3x\] Now if I told you that x = 0 what would you do to find f(x) ?
will the answer be 0,3,6
Close.. Should be 0, 6, and 6.
Yea i didn't do that f(1) right
At least according to what you wrote initially.
Thanks so much I think I got it can I be a fan
So.. \[f(-1) = 3(-1)^2 - 3(-1)\]
Thanks so much