## anonymous 5 years ago i don't understand what to do here: Find ds/dt when θ=π if s=cosθ and dθ/dt=-6...

1. anonymous

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given $s=\cos\theta$ so, we can say $\frac{ds}{dt}=-\sin\theta \frac{d\theta}{dt}$ also given that $\theta = \pi, \frac{d\theta}{dt}=-6$ so we get $\frac{ds}{dt}=-\sin\theta \frac{d\theta}{dt}=0$