anonymous
  • anonymous
lim_{x rightarrow -infty} {{4 - 7x} over {2 + 3x}}
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\lim_{x \rightarrow -\infty} {{4 - 7x} \over {2 + 3x}}\]
anonymous
  • anonymous
im gonna say lopital's rule.. so -7/3. im sure its wrong though, i cant find anything to factor out.
anonymous
  • anonymous
factor an x from the top and bottom.

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anonymous
  • anonymous
\[\frac{x(-7+\frac{4}{x})}{x(3+\frac{2}{x})}\]
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
So you should get \(\frac{-7}{3}\) when you cancel the x and take the limit because the two fractions on top and bottom will go to 0.
anonymous
  • anonymous
Right. Now i can go on. thks

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