A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
revolve the region in first quadrant bounded by y = x^2 , y = x , about line x = 2, using washer method
anonymous
 5 years ago
revolve the region in first quadrant bounded by y = x^2 , y = x , about line x = 2, using washer method

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\pi \int\limits_{0}^{4}(2x)^{2}(2x ^{2})^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0srry its been a long time.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the region is from (0,0) to (1,1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh sorry sorry forgot about the bounds. assumed that x22 was also a bound

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also youre using dy , not x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ure supposed to use dx?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since its horizontal integration

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just the wrong values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its wrong in other ways!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok lets do it again: \[\pi \int\limits_{0}^{1} (2x)^{2}(2x ^{2})^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this HASSSSS TO BE RIGHT

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its pi* integral ( y  2)^2  (sqrt y  2)^2
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.