anonymous
  • anonymous
hi i need help with rationals
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[4/x+1=3/x+2\]
anonymous
  • anonymous
Is that: a) \(\frac{4}{x} +1 = \frac{3}{x} + 2\) b)\(\frac{4}{x+1} = \frac{3}{x+2}\) c) neither a nor b
anonymous
  • anonymous
b

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anonymous
  • anonymous
Multiply both sides by (x+1)(x+2). Then solve in the usual way. You just need to stipulate that \(x\ne-1 \text{ and } x\ne -2\).
anonymous
  • anonymous
:( i stil not understand
anonymous
  • anonymous
\[\frac{4}{x+1}=\frac{3}{x+2}\] \[(x+1)(x+2) *\frac{4}{x+1}=\frac{3}{x+2} * (x+1)(x+2)\]
anonymous
  • anonymous
then the answer should be 7x+9 over (x+1)(x+2) im i correct.?
anonymous
  • anonymous
No.. There should be no denominator when you're done You should simply have x = a number.
anonymous
  • anonymous
\[\frac{(x+1)(x+2)}{1}*\frac{4}{x+1} = \frac{3}{x+2}*\frac{(x+1)(x+2)}{1}\] \[4(x+2) = 3(x+1)\]
anonymous
  • anonymous
oh gawsh.!
anonymous
  • anonymous
And continue from there.
anonymous
  • anonymous
ohkay i multiplied nd got 4x+8=3x+3
anonymous
  • anonymous
x=5 correct
anonymous
  • anonymous
I have x = -5
anonymous
  • anonymous
yes thank you sooo much.!

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