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anonymous
 5 years ago
hi i need help with rationals
anonymous
 5 years ago
hi i need help with rationals

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is that: a) \(\frac{4}{x} +1 = \frac{3}{x} + 2\) b)\(\frac{4}{x+1} = \frac{3}{x+2}\) c) neither a nor b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiply both sides by (x+1)(x+2). Then solve in the usual way. You just need to stipulate that \(x\ne1 \text{ and } x\ne 2\).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:( i stil not understand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{4}{x+1}=\frac{3}{x+2}\] \[(x+1)(x+2) *\frac{4}{x+1}=\frac{3}{x+2} * (x+1)(x+2)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then the answer should be 7x+9 over (x+1)(x+2) im i correct.?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No.. There should be no denominator when you're done You should simply have x = a number.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{(x+1)(x+2)}{1}*\frac{4}{x+1} = \frac{3}{x+2}*\frac{(x+1)(x+2)}{1}\] \[4(x+2) = 3(x+1)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And continue from there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohkay i multiplied nd got 4x+8=3x+3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes thank you sooo much.!
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