anonymous
  • anonymous
A box with an open top is to be constructed out of a rectangular piece of cardboard with dimensions length=8 ft and width=9 ft by cutting a square piece out of each corner and turning the sides up. Determine the length x of each side of the square that should be cut which would maximize the volume of the box.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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radar
  • radar
Let x equal the dimension of the corner that is going to be cut out (so the sides fold up and make a box. This x will also equal the height of the box. The dimensions of the box will then be Length=8-2x (corners cut out at each end.) width =9-2x. Volume will equal l*w*h. Please review this and see if you follow with understanding.
radar
  • radar
\[V=(9-2x)(8-2x) x\]
anonymous
  • anonymous
Following you so far. haha, that's about as far as I got on my own though. lol

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radar
  • radar
\[V=(72-34X+4X ^{2})x\]
radar
  • radar
\[V=72x-34x ^{2}+4x ^{3}\]
radar
  • radar
Rearranging in to a more standard form\[V=4x ^{3}-34x ^{2}+72x\] Are you still with me?
anonymous
  • anonymous
Yep. Then we take the derivative?
radar
  • radar
Yes and set to zero and then solve for x.
radar
  • radar
Let me know what you get.
anonymous
  • anonymous
Derivative of.. \[12x ^{2} -68x +72\] ?
radar
  • radar
Yes, to make it easier set it to zero and divide both sides by 4 getting:
radar
  • radar
\[3x ^{2}-17x+18=0\]
anonymous
  • anonymous
so I'm gettinggg.. \[1/6 (17\pm \sqrt{73}\]
anonymous
  • anonymous
with another ) at the end.. lol
radar
  • radar
You're ahead of me. I was trying to factor before going for the quadratic equation. It looks like that was the way to go. I'll check it out and if there is an error I will be back. Remember this is the dimension of the corner cut out, to get the dimensions of the box you will subtract twice this from the 8' and 9'
anonymous
  • anonymous
How do I know which x value to use though, the plus gives me approximately 1.4 and the minus gives me approximately 4.3
anonymous
  • anonymous
Nevermind I've got it. haha thank you!
radar
  • radar
Good mic61 your computation was correct. Good day.

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