80=1/9x^2+11/3x solve for x

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80=1/9x^2+11/3x solve for x

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Do you mean \[80=\frac{1}{9}x^2+\frac{11}{3}x\]?
If so, multiply everything through by the highest denominator to eliminate your fractions. Here, multiply through by 9 to get\[720=x^2+33x\]
This is quadratic, so you have\[x^2+33x-720=0\] which can be factored into \[(x-15)(x+48)=0\]

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For this to be true, either one, or both, of the factors have to be zero. Hence, your x-values are\[x=15,x=-48\]
thank you!
np

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