## anonymous 5 years ago 80=1/9x^2+11/3x solve for x

1. anonymous

Do you mean $80=\frac{1}{9}x^2+\frac{11}{3}x$?

2. anonymous

If so, multiply everything through by the highest denominator to eliminate your fractions. Here, multiply through by 9 to get$720=x^2+33x$

3. anonymous

This is quadratic, so you have$x^2+33x-720=0$ which can be factored into $(x-15)(x+48)=0$

4. anonymous

For this to be true, either one, or both, of the factors have to be zero. Hence, your x-values are$x=15,x=-48$

5. anonymous

thank you!

6. anonymous

np