anonymous
  • anonymous
80=1/9x^2+11/3x solve for x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Do you mean \[80=\frac{1}{9}x^2+\frac{11}{3}x\]?
anonymous
  • anonymous
If so, multiply everything through by the highest denominator to eliminate your fractions. Here, multiply through by 9 to get\[720=x^2+33x\]
anonymous
  • anonymous
This is quadratic, so you have\[x^2+33x-720=0\] which can be factored into \[(x-15)(x+48)=0\]

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anonymous
  • anonymous
For this to be true, either one, or both, of the factors have to be zero. Hence, your x-values are\[x=15,x=-48\]
anonymous
  • anonymous
thank you!
anonymous
  • anonymous
np

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