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anonymous
 5 years ago
An open box is to be constructed so that the length of the base is 4 times larger than the width of the base. If the cost to construct the base is 4 dollars per square foot and the cost to construct the four sides is 3 dollars per square foot, determine the dimensions for a box to have volume = 71 cubic feet which would minimize the cost of construction.
anonymous
 5 years ago
An open box is to be constructed so that the length of the base is 4 times larger than the width of the base. If the cost to construct the base is 4 dollars per square foot and the cost to construct the four sides is 3 dollars per square foot, determine the dimensions for a box to have volume = 71 cubic feet which would minimize the cost of construction.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which part of the problem is giving you trouble?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, I thought that I'd figured it out.. but when I put my answer into the computer program, it says I'm wrong. lol What I did was create an equation for the surface area. I used the volume for equation to write height in terms of width, then I substituted 4w in for lenth in the s.a. equation as well as 71/(4w^2) for the height in the surface area equation. After that I found the derivative, set it to zero and solved. I think I made a dumb mistake somewhere, so I asked on here to see if someone would just resolve for me, because I'm not catching it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have that the base length is 4 times larger than the width so you can eliminate one or the other. You have an equation for the volume, and can use that to find height in terms of the variable you kept from the first equation.. Then you can rewrite your cost function in terms of just one of the variables and take the derivative to find where it has a minimum.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what I tried to do.. lol, I'm pretty sure my math is just wrong somewhere.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\(L=4W\) \(LWH=71 \implies 4W^2H = 71\implies H = \frac{71}{4W^2}\) \(Cost = 4LW + 3(2LH) + 3(2(WH))\) \(= 16W^2 + \frac{6(4W)(71)}{4W^2} + \frac{6W(71)}{4W^2}\) etc.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right. That's what I did. Could you just continue the algebra to simplify it? Once its simplified I shoouulld be fine taking the derivative and setting it to zero and all that fun.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is that the same cost function you got?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I had written substituted in the 4w for the length and simplified before I put in the substitution for height.. so I had 2wh +2h(4w) +2w(4w), and then made it 10wh +8w^2 before I put in the 71/(4w^2).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know if that would have made a difference though.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That looks like a surface area function though, not the cost function. You forgot to factor in the costs of each of the sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ooohhh. I didn't even realize I had left that out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Simplifying we just end up with \(Cost =16w^2 + \frac{1065}{2w}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so our derivative would be.. 32 w 1065/(2^w2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay I've got it. Thank you :)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Just to check myself did you come out with: width=2.5 Length = 10 height =2.84
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