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anonymous
 5 years ago
The velocity (in meters/sec) of a particle moving along a straight line is given by v(t)=3t^2+2t+3, where t is measured in seconds.
Answer the following questions given that the initial positions(0)=6.
a. What is the meter position of the particle at any given time t?
b. What is the meter position of the body at time t=2?
c.What is the meter position of the particle at time t=10?
d. What is the displacement of the particle on the time interval 2<t<10?
anonymous
 5 years ago
The velocity (in meters/sec) of a particle moving along a straight line is given by v(t)=3t^2+2t+3, where t is measured in seconds. Answer the following questions given that the initial positions(0)=6. a. What is the meter position of the particle at any given time t? b. What is the meter position of the body at time t=2? c.What is the meter position of the particle at time t=10? d. What is the displacement of the particle on the time interval 2<t<10?

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0part a) you integrate the velocity function to obtain the position function, keep in mind initial position part b) use function from part a) and plug in t=2 part c) same as before use t =10 part d) this is how far the particle has moved so f(10)  f(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We haven't gotten to integrals yet in class.. Exactly how do I do that?

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0hmm i guess you could graph the velocity function and estimate the area under the graph from 2 to 10. that would answer part d)

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0you could also estimate position using the velocity at each t. so p(0) = 6 and v(0) = 3 then p(1) = 9 you assume particle moved 3meters that first second find v(1) to get p(2) and so on.. *p(t) is position

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've already got it. Thanks though :)
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