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anonymous

  • 5 years ago

The velocity (in meters/sec) of a particle moving along a straight line is given by v(t)=3t^2+2t+3, where t is measured in seconds. Answer the following questions given that the initial positions(0)=6. a. What is the meter position of the particle at any given time t? b. What is the meter position of the body at time t=2? c.What is the meter position of the particle at time t=10? d. What is the displacement of the particle on the time interval 2<t<10?

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  1. dumbcow
    • 5 years ago
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    part a) you integrate the velocity function to obtain the position function, keep in mind initial position part b) use function from part a) and plug in t=2 part c) same as before use t =10 part d) this is how far the particle has moved so f(10) - f(2)

  2. anonymous
    • 5 years ago
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    We haven't gotten to integrals yet in class.. Exactly how do I do that?

  3. dumbcow
    • 5 years ago
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    hmm i guess you could graph the velocity function and estimate the area under the graph from 2 to 10. that would answer part d)

  4. dumbcow
    • 5 years ago
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    you could also estimate position using the velocity at each t. so p(0) = 6 and v(0) = 3 then p(1) = 9 you assume particle moved 3meters that first second find v(1) to get p(2) and so on.. *p(t) is position

  5. anonymous
    • 5 years ago
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    I've already got it. Thanks though :)

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