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anonymous

  • 5 years ago

need help could someone walk me through this....6x+9-4x=3x+11

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  1. anonymous
    • 5 years ago
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    ok. So first pick what side you want to have the x's in. normally they are on the left side.

  2. anonymous
    • 5 years ago
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    so get your x's on the left side following your oder of operations.

  3. anonymous
    • 5 years ago
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    combine the terms right

  4. anonymous
    • 5 years ago
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    yup

  5. anonymous
    • 5 years ago
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    what do you get?

  6. anonymous
    • 5 years ago
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    You should get 6x-4x-3x=11-9

  7. anonymous
    • 5 years ago
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    did you get this?

  8. anonymous
    • 5 years ago
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    rt sorry typing sucks

  9. anonymous
    • 5 years ago
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    yes

  10. anonymous
    • 5 years ago
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    o.k now combine the terms.

  11. anonymous
    • 5 years ago
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    just add/ subtract respectively

  12. anonymous
    • 5 years ago
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    what do you get?

  13. anonymous
    • 5 years ago
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    13x-11-9

  14. anonymous
    • 5 years ago
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    13x=11-9

  15. anonymous
    • 5 years ago
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    remember we want to keep the x's with the x's and the integers with the integers.

  16. anonymous
    • 5 years ago
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    dont forget about your signs. Look at the signs: 6x-4x-3x

  17. anonymous
    • 5 years ago
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    notice that we are adding two negative numbers.

  18. anonymous
    • 5 years ago
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    remember (-3)+(-3)=-6

  19. anonymous
    • 5 years ago
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    -6-6=-12

  20. anonymous
    • 5 years ago
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    -13

  21. anonymous
    • 5 years ago
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    the only time when two negative numbers become positive is when we multiply them

  22. anonymous
    • 5 years ago
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    right gotthat

  23. anonymous
    • 5 years ago
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    so what would -4x-3x be?

  24. anonymous
    • 5 years ago
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    -7x

  25. anonymous
    • 5 years ago
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    cool. So what is 6x-7x

  26. anonymous
    • 5 years ago
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    -1

  27. anonymous
    • 5 years ago
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    almost. -x

  28. anonymous
    • 5 years ago
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    forgot 1x is same asx

  29. anonymous
    • 5 years ago
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    so we got the left side taken care. The right side should give us 2

  30. anonymous
    • 5 years ago
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    so we have -x=2. we are almost done

  31. anonymous
    • 5 years ago
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    all that is left is getting rid of the negative. All we need to do is divide by a negative.

  32. anonymous
    • 5 years ago
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    so the answer is x=-2.

  33. anonymous
    • 5 years ago
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    see i get lost on when to change the operation like sub to add or change neg to pos

  34. anonymous
    • 5 years ago
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    whenever you have the equation in just x's on one side and integers on the right, then you can divide.

  35. anonymous
    • 5 years ago
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    3x=53, x=53/3. Its ok to divide. 3x=53+5x, you can divide but it will just be messy: x=(53+5x)/3. Besides we have to solve for x and that just complicated things.

  36. anonymous
    • 5 years ago
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    3x-5x=53, -2x=53, x=-53/2

  37. anonymous
    • 5 years ago
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    ok so when i see a - sign its the same as neg

  38. anonymous
    • 5 years ago
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    correct.

  39. anonymous
    • 5 years ago
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    3x-5x is -2x......but when i have an equation here let me show u if u have time?

  40. anonymous
    • 5 years ago
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    yeah. its cool. show away.

  41. anonymous
    • 5 years ago
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    4(3x-5)=-4x+27

  42. anonymous
    • 5 years ago
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    what screws me up is when im not sure if i add or sub

  43. anonymous
    • 5 years ago
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    so its 12x-20=4x+27

  44. anonymous
    • 5 years ago
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    then move the smaller x ?

  45. anonymous
    • 5 years ago
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    its really up to you. It does not matter. The answer will work out the same.

  46. anonymous
    • 5 years ago
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    you just have to remember to keep your x's with your x's on one side of the equation and your integers on the other side.

  47. anonymous
    • 5 years ago
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    whether you want to keep the x on the right or left side it does not matter.

  48. anonymous
    • 5 years ago
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    12x-4x=27+20 -20-27=4x-12x 8x=47 -47=-8x x=47/8 47/8=x (negatives cancel.)

  49. anonymous
    • 5 years ago
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    makes sense sry im really not sow....lol always had problem with math

  50. anonymous
    • 5 years ago
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    slow..lol

  51. anonymous
    • 5 years ago
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    math just takes time. After graduating from high school i did my own thing for 4 year not worrying about school. After 4 yrs I decided to go to college. Took a placement test and place in pre-algebra. I have been working my way up ever since.

  52. anonymous
    • 5 years ago
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    just be patient with it.

  53. anonymous
    • 5 years ago
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    thats exactly what im doin now...but its been 14 yrs since ive been to school

  54. anonymous
    • 5 years ago
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    what math u doin now

  55. anonymous
    • 5 years ago
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    im in differential equations and linear algebra.

  56. anonymous
    • 5 years ago
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    cool hey thx for ur help im keith btw

  57. anonymous
    • 5 years ago
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    r u on here often

  58. anonymous
    • 5 years ago
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    no worries. yeah. Im usually asking questions as well. We all need help.

  59. anonymous
    • 5 years ago
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    well good luck on your math studies.

  60. anonymous
    • 5 years ago
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    u too take care

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