anonymous
  • anonymous
need help could someone walk me through this....6x+9-4x=3x+11
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
ok. So first pick what side you want to have the x's in. normally they are on the left side.
anonymous
  • anonymous
so get your x's on the left side following your oder of operations.
anonymous
  • anonymous
combine the terms right

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anonymous
  • anonymous
yup
anonymous
  • anonymous
what do you get?
anonymous
  • anonymous
You should get 6x-4x-3x=11-9
anonymous
  • anonymous
did you get this?
anonymous
  • anonymous
rt sorry typing sucks
anonymous
  • anonymous
yes
anonymous
  • anonymous
o.k now combine the terms.
anonymous
  • anonymous
just add/ subtract respectively
anonymous
  • anonymous
what do you get?
anonymous
  • anonymous
13x-11-9
anonymous
  • anonymous
13x=11-9
anonymous
  • anonymous
remember we want to keep the x's with the x's and the integers with the integers.
anonymous
  • anonymous
dont forget about your signs. Look at the signs: 6x-4x-3x
anonymous
  • anonymous
notice that we are adding two negative numbers.
anonymous
  • anonymous
remember (-3)+(-3)=-6
anonymous
  • anonymous
-6-6=-12
anonymous
  • anonymous
-13
anonymous
  • anonymous
the only time when two negative numbers become positive is when we multiply them
anonymous
  • anonymous
right gotthat
anonymous
  • anonymous
so what would -4x-3x be?
anonymous
  • anonymous
-7x
anonymous
  • anonymous
cool. So what is 6x-7x
anonymous
  • anonymous
-1
anonymous
  • anonymous
almost. -x
anonymous
  • anonymous
forgot 1x is same asx
anonymous
  • anonymous
so we got the left side taken care. The right side should give us 2
anonymous
  • anonymous
so we have -x=2. we are almost done
anonymous
  • anonymous
all that is left is getting rid of the negative. All we need to do is divide by a negative.
anonymous
  • anonymous
so the answer is x=-2.
anonymous
  • anonymous
see i get lost on when to change the operation like sub to add or change neg to pos
anonymous
  • anonymous
whenever you have the equation in just x's on one side and integers on the right, then you can divide.
anonymous
  • anonymous
3x=53, x=53/3. Its ok to divide. 3x=53+5x, you can divide but it will just be messy: x=(53+5x)/3. Besides we have to solve for x and that just complicated things.
anonymous
  • anonymous
3x-5x=53, -2x=53, x=-53/2
anonymous
  • anonymous
ok so when i see a - sign its the same as neg
anonymous
  • anonymous
correct.
anonymous
  • anonymous
3x-5x is -2x......but when i have an equation here let me show u if u have time?
anonymous
  • anonymous
yeah. its cool. show away.
anonymous
  • anonymous
4(3x-5)=-4x+27
anonymous
  • anonymous
what screws me up is when im not sure if i add or sub
anonymous
  • anonymous
so its 12x-20=4x+27
anonymous
  • anonymous
then move the smaller x ?
anonymous
  • anonymous
its really up to you. It does not matter. The answer will work out the same.
anonymous
  • anonymous
you just have to remember to keep your x's with your x's on one side of the equation and your integers on the other side.
anonymous
  • anonymous
whether you want to keep the x on the right or left side it does not matter.
anonymous
  • anonymous
12x-4x=27+20 -20-27=4x-12x 8x=47 -47=-8x x=47/8 47/8=x (negatives cancel.)
anonymous
  • anonymous
makes sense sry im really not sow....lol always had problem with math
anonymous
  • anonymous
slow..lol
anonymous
  • anonymous
math just takes time. After graduating from high school i did my own thing for 4 year not worrying about school. After 4 yrs I decided to go to college. Took a placement test and place in pre-algebra. I have been working my way up ever since.
anonymous
  • anonymous
just be patient with it.
anonymous
  • anonymous
thats exactly what im doin now...but its been 14 yrs since ive been to school
anonymous
  • anonymous
what math u doin now
anonymous
  • anonymous
im in differential equations and linear algebra.
anonymous
  • anonymous
cool hey thx for ur help im keith btw
anonymous
  • anonymous
r u on here often
anonymous
  • anonymous
no worries. yeah. Im usually asking questions as well. We all need help.
anonymous
  • anonymous
well good luck on your math studies.
anonymous
  • anonymous
u too take care

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