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anonymous
 5 years ago
Find a vector that the same direction as −2i + 4j+ 2k but that has length 6.
anonymous
 5 years ago
Find a vector that the same direction as −2i + 4j+ 2k but that has length 6.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0desperately waiting for ur reply...so fed up with this problem right now !!! help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do share ur views on this plss

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am new here, on this site, looks fun

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0surely it is !!! nothing lesser than a boon to the students !!! getting live help for free is just awesome

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0feels like v r a community sharing its knowledge

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am graduating highschool this spring

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the only bad thing is that me and my boyfriend are going to different universities :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Carnegie Mellon University

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what degree wer u in ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Computer Science, I know this sounds strange because I am a girl, but I LOVE computer science and programming

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats good.....computers r not just monopoly of boyzzz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ankur, you still need an answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You just need to find the unit vector of u and multiply it by 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah got it !!! cheers !!!

nikvist
 5 years ago
Best ResponseYou've already chosen the best response.0\[2i+4j+2k=\sqrt{(2)^2+4^2+2^2}=2\sqrt{6}\] \[\vec{a}=\alpha(2i+4j+2k)\quad,\quad\alpha=\frac{6}{2\sqrt{6}}=\frac{\sqrt{6}}{2}\] \[vec{a}=\frac{\sqrt{6}}{2}(2i+4j+2k)=\sqrt{6}i+2\sqrt{6}j+\sqrt{6}k\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey one more short question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0unit vector that is perpendicular to the xzplane

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(1,0,0) lies in x, (0,0,1) lies in z, so (0,1,0) will lie in y which is perpendicular to xz.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@nikwist : could you please tell how do u type square roots like this on screen?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and it's a unit vector.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u r so intelligent !!! no wonder you have so many fans !!! thanx a lot again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0np...fan me if you haven't :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have...do u have any idea how nikwist wrote his answers like that above?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, go into equation editor below, and there's a set of boxes to the right you can use. You can also type, sqrt{x} directly into the equation line to get\[\sqrt{x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cheers !!! u r really a lifesaver
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