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anonymous

  • 5 years ago

evaluate lim (x^2-1)/(sqrt(x)-1) x-> the answer in the book says 2

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  1. anonymous
    • 5 years ago
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    lim x->1 x^2-1/ sqrt(x) -1 = lim x->1 ( sqrt(x) -1 )( sqrt(x) +1 ) / ( sqrt(x) -1 ) = lim x->1 ( sqrt(x) +1) pluggin in the values , we get = ( sqrt(1) +1) = 1 +1 =2 hope that helps !!! let me know if u r satisfied...

  2. anonymous
    • 5 years ago
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    thank you very much!

  3. anonymous
    • 5 years ago
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    I dont understand the first step

  4. anonymous
    • 5 years ago
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    okay let me explain

  5. anonymous
    • 5 years ago
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    remember the formula a^2 - b^2 = (a - b) (a +b)

  6. anonymous
    • 5 years ago
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    yes

  7. anonymous
    • 5 years ago
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    (sqrt(x)-1) (sqrt(x)+1) does that equal x-1?

  8. anonymous
    • 5 years ago
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    u got it ...cheers !!!!

  9. anonymous
    • 5 years ago
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    but the original problem has a numerator of x^2-1 not X-1

  10. anonymous
    • 5 years ago
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    the square root of x^2 is only x

  11. anonymous
    • 5 years ago
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    okay !!! then make it as (x -1)(x +1) which equals to (sqrt(x)-1) (sqrt(x)+1) (x +1) and now plug in the values

  12. anonymous
    • 5 years ago
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    but thats like we are getting 4

  13. anonymous
    • 5 years ago
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    I thought this one looked so simple

  14. anonymous
    • 5 years ago
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    r u sure that u read the statement correct?

  15. anonymous
    • 5 years ago
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    evaluate the indicated limit, if it exists. lol (x-1)/(sqrt(x)-1) I was wrong

  16. anonymous
    • 5 years ago
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    yes.......the limit does exist which is 4

  17. anonymous
    • 5 years ago
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    your original answer is right, Thank you very much for your help!

  18. anonymous
    • 5 years ago
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    4 or 2 ? :)

  19. anonymous
    • 5 years ago
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    2 because I had the problem wrong the numerator is (x-1)

  20. anonymous
    • 5 years ago
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    ahh !!!!!! finally we r there !!! gud luck with ur maths ..

  21. anonymous
    • 5 years ago
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    thanks bro

  22. anonymous
    • 5 years ago
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    no worries !!!!

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