evaluate lim (x^2-1)/(sqrt(x)-1) x-> the answer in the book says 2

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evaluate lim (x^2-1)/(sqrt(x)-1) x-> the answer in the book says 2

Mathematics
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lim x->1 x^2-1/ sqrt(x) -1 = lim x->1 ( sqrt(x) -1 )( sqrt(x) +1 ) / ( sqrt(x) -1 ) = lim x->1 ( sqrt(x) +1) pluggin in the values , we get = ( sqrt(1) +1) = 1 +1 =2 hope that helps !!! let me know if u r satisfied...
thank you very much!
I dont understand the first step

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okay let me explain
remember the formula a^2 - b^2 = (a - b) (a +b)
yes
(sqrt(x)-1) (sqrt(x)+1) does that equal x-1?
u got it ...cheers !!!!
but the original problem has a numerator of x^2-1 not X-1
the square root of x^2 is only x
okay !!! then make it as (x -1)(x +1) which equals to (sqrt(x)-1) (sqrt(x)+1) (x +1) and now plug in the values
but thats like we are getting 4
I thought this one looked so simple
r u sure that u read the statement correct?
evaluate the indicated limit, if it exists. lol (x-1)/(sqrt(x)-1) I was wrong
yes.......the limit does exist which is 4
your original answer is right, Thank you very much for your help!
4 or 2 ? :)
2 because I had the problem wrong the numerator is (x-1)
ahh !!!!!! finally we r there !!! gud luck with ur maths ..
thanks bro
no worries !!!!

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