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anonymous

  • 5 years ago

find lcm of y^2-81, 9y+81

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  1. anonymous
    • 5 years ago
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    The multiples in y^2-81 are\[y^2-81=(y-9)(y+9)\]since this is a difference of two squares. The multiples of 9y+81 are\[9(y+9)\]You'll notice that the only multiple the two numbers (expressions) have in common is (y+9), so \[y+9\]is your LCM.

  2. anonymous
    • 5 years ago
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    hey

  3. anonymous
    • 5 years ago
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    hello

  4. anonymous
    • 5 years ago
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    anyone here from Carnegie Mellon University?

  5. anonymous
    • 5 years ago
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    :)

  6. anonymous
    • 5 years ago
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    No, sorry.

  7. anonymous
    • 5 years ago
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    no prob... just found this site randomly

  8. anonymous
    • 5 years ago
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    haha, me too...

  9. anonymous
    • 5 years ago
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    so, are you staff here? I mean you got this HERO status

  10. anonymous
    • 5 years ago
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    no, not staff, just answered a lot of questions :)

  11. anonymous
    • 5 years ago
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    alright, well, good luck :) I just got one fan, even though I did not do anything or help anyone, strange :)

  12. anonymous
    • 5 years ago
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    lol, take what you can get!

  13. anonymous
    • 5 years ago
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    haha :) yeah.. i always take everything I can

  14. anonymous
    • 5 years ago
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    alright guyz, i came, i saw, and now its time to leave, see you next time

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spraguer (Moderator)
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