anonymous
  • anonymous
Field biologist Leema is out gathering fungi in the rain forest when she stumbles into a 4.0 m deep pit lined with killer snakes. Nasteho Warrior Princess hears Leema's cries for help and dashes to the pit to save her. Nasteho lowers a vine down into the pit - the breaking strength of the vine is 8.00x10^2 N - and starts to pull Leema out. If Leema's weight is 602 N, what is the maximum acceleration Nasteho can use to save her? How long does it take to pull her out of danger?
Physics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
d = 4.0 m F(vine) = 800 N F(weight) = - 602 N g = 9.81 m/s^2 \[F(weight) = mg\]so m = (602)/(9.81) = 61.4 kg The net force acting on Leema is: F(net) = F(vine) + F(weight) = 800 - 602 = 198 N \[\Sigma F = ma\]so a = (198)/(61.4) = 3.2 m/s^2 \[d = 1/2at^2\]so t^2 = 4/(0.5*3.2) = 4/1.6 = 2.5 s^2 thus, t = 1.58 s Answer: a = 3.2 m/s^2; t = 1.58 s
anonymous
  • anonymous
Conceptually, we can assume that Nasteho is pulling the vine with a force that is equal to the breaking strength of the vine. As a result, the vine exerts a positive (upwards) force, while gravity exerts a negative (downwards) force. The net force acting on Leema will be equal to the sum of these two forces. The net force could then be used to find Leema's acceleration.
anonymous
  • anonymous
so now do i need to fine leema's acceleratin?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
find*
anonymous
  • anonymous
You know that the net force acting on Leema is 198 N. Using the formula F = ma, you can find Leema's acceleration. And you need to find Leema's acceleration in order to find the time required to pull her out of danger.
anonymous
  • anonymous
umm...ok so do i hav F=ma?
anonymous
  • anonymous
Yes, you use F = ma. See my calculations above.

Looking for something else?

Not the answer you are looking for? Search for more explanations.